3 years ago

HURRY PLEASE I really need this to pass my class

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

6 0

Problem 1.

$\sqrt{\dfrac{2160x^8}{60x^2}} =$

$= \sqrt{36x^6}$

$= 6x^3$

Problem 2.

$\sqrt{400x^{100}} =$

$= 20x^{50}$

Problem 3.

$\sqrt{100x^{36}} =$

$= 10x^{18}$

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24(9) = 2x i need help with this

Degger [83]

Answer:

24×9 = 2x

216 = 2x

216÷2 = x

108 = x

x=108

4 0

3 years ago

F(x) = 3x<br> g(x) = x2 – 5x - 9<br> Find (fºg)(x).

Eddi Din [679]

Answer:

$\boxed{(f.g)(x) = 3 {x}^{3} - 15 {x}^{2} - 27x}$

Given:

$f(x) = x + 2 \\ \\ g(x) = 3x + 5$

To Find:

$(f.g)(x) = f(x) \times g(x)$

Step-by-step explanation:

$= > f(x) \times g(x) = (3x)( {x}^{2} - 5x - 9) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3x \times {x}^{2} ) - (3x \times 5x) - (3x \times 9)\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3 {x}^{3} - 15 {x}^{2} - 27x$