mrs. houston puts 5 ounces of snack mix in each bag how many pounds of snack mix does she need to fill 32 bags

Is 4 18/12 equal to 5 6/12?

Tom [10]

Answer:

Yes, 4 18/12 is equal to 5 6/12.

Step-by-step explanation:

Given that

4 18/12 = 5 6/12

11/2 = 11/2

Yes both are equal.

7 0

3 years ago

Which expressions are equivalent

Kazeer [188]

Step-by-step explanation:

The first set is equivalent.

We obtain the right-hand side by swapping places of the terms.

5 0

3 years ago

Which shows the equation 3y – x = 6 written in slope-intercept form?

laila [671]

Slope intercept form : y = mx + b

3y - x = 6 ....add x to both sides
3y = x + 6 ...divide both sides by 3
y = x/3 + 2 <== slope intercept form

7 0

3 years ago

Michael cycles 4 kilometers during each trip to work. Write an equation that shows the relationship between the number of trips

Lady bird [3.3K]

Answer:

The equation that represents the total distance travelled by numbers of times he goes to work by Michael is y = 4*x

Step-by-step explanation:

Since Michael has to travel 4 km each time he goes to work if he goes to work 2 times he'll have to travel 8 km, if he goes 3 times he'll have to travel 12 km. If we keep doing this we'll realize that the distance travelled by Michael is given by the number of times he goes to work multiplied by 4. The equation that represents that is:

y = 4*x

4 0

3 years ago

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago