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Murljashka [212]
2 years ago
7

Hi! ❤️ there looking for help on this giving brainliest if able to.

Mathematics
2 answers:
-Dominant- [34]2 years ago
8 0

Answer:

true......................

love history [14]2 years ago
8 0
The first two should be true and the second two should be false. I am sorry if I am incorrect but I am almost positive that is correct.

Hope this helps :)
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Which defines a circle
SIZIF [17.4K]
Circle<span> is the locus of points equidistant from a given point, the center of the </span>circle<span>. The common distance from the center of the </span>circle<span> to its points is called radius. Thus a </span>circle<span> is completely </span>defined<span> by its center (O) and radius (R): C(O, R) = O(R) = {x: dist(O, x) = R}.
Easier explanation: </span><span>A </span>circle<span> is a plane figure contained by one line such that all the straight lines falling upon it from one point among those lying within the figure are equal to one another.</span>
4 0
3 years ago
C(a + b)- d = f, for a
Galina-37 [17]
Hopes this helps you out

3 0
3 years ago
Read 2 more answers
Chicos estoy en un aprieto ayudarme pls Sabiendo que una falda es 5 € más cara que una blusa y que si compro 6 faldas y 4 blusas
poizon [28]

Answer:

El precio de la falda es 50 €.

Step-by-step explanation:

Lo que sabemos:

F = 5 + B   (1)

En donde F es por falda y B por blusa.

Si compras 6 faldas y 4 blusas y pagas 480 €:

6F + 4B = 480  (2)

Entonces, al introducir la ecuación (1) en (2) podemos hallar el precio de cada falda.

6F + 4B = 480

6(5 + B) + 4B = 480

10B = 480 - 30

B = \frac{450}{10} = 45  

Finalmente, el precio de la falda se puede encontar con la ecuación (1):

F = 5 + 45 = 50

Por lo tanto, el precio de la falda es 50 €.  

Espero que te sea de utilidad!      

7 0
3 years ago
8 + (-3) integers topic
dalvyx [7]
If you’re asking for the answer, it’s 5
3 0
3 years ago
Solve the equation x+3/x-4 = x-5/x+4
Serga [27]

Answer:

\large\boxed{x=\dfrac{1}{2}}

Step-by-step explanation:

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\\\\\text{Domain:}\ x-4\neq0\ \wedge\ x+4\neq0\\\\x\neq4\ \wedge\ x\neq-4\\\\D:x\in\mathbb{R}-\{-4,\ 4\}

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\qquad\text{cross multiply}\\\\(x+3)(x+4)=(x-4)(x-5)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x)(x)+(x)(4)+(3)(x)+(3)(4)=(x)(x)+(x)(-5)+(-4)(x)+(-4)(-5)\\\\x^2+4x+3x+12=x^2-5x-4x+20\qquad\text{combine like terms}\\\\x^2+(4x+3x)+12=x^2+(-5x-4x)+20\\\\x^2+7x+12=x^2-9x+20\qquad\text{subtract}\ x^2\ \text{from both sides}\\\\7x+12=-9x+20\qquad\text{subtract 12 from both sides}\\\\7x=-9x+8\qquad\text{add}\ 9x\ \text{to both sides}\\\\16x=8\qquad\text{divide both sides by 16}\\\\x=\dfrac{8}{16}\\\\x=\dfrac{8:8}{16:8}\\\\x=\dfrac{1}{2}\in D

7 0
3 years ago
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