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2 years ago

Is the relationship below linear, exponential, or neither?

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

5 0

Answer:

Linear

Step-by-step explanation:

It is linear because you are adding where exponential has to do with multiplying.

You might be interested in

S<br>solve for X<br>2x - Px = 5

maxonik [38]

Answer:

$2x - P = 5 \\ x(2 - P) = 5 \\ \boxed{x = \frac{5}{(2 - P)} }$

5 0

3 years ago

On a basketball team, the following players made most of the 56 points made during the last basketball game.

Ivanshal [37]

Answer:

7.75

Step-by-step explanation:

56-27-21-0.25=7.75

4 0

3 years ago

You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample

Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=160)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{160}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 1.96$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{1.96(160)}{78.4})^2 =16$

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And now we can replace the new value of Me and see what we got, like this:

$n=(\frac{1.96*160}{60})^2 =27.32$

And if we round up the answer we see that the value of n to ensure the margin of error required $Me=\pm 60$ $ is n=28.

5 0

2 years ago

I need explanations. I don't understand this. Please click on the picture.

AlekseyPX

1. find the area of the two triangles, including the shaded section. the formula for this is a=1/2bh

the height and base are both 24 inches. this is because you add the 10 from the side of the square to the 14 that is given

so:

a=1/2(24)(24)
a=(12)(24)
a=288 sq. inches

since there are two triangles, you would multiply the area by 2

a=2(288)
a=576 sq. inches

now, since you only need the unshaded section, you have to take away the shaded section, which is a square. to do this, you must calculate the area of the square and take it away from the area of both triangles.

a=576-(lw)
a=576- (10)(10)
a=576-100
a=476 sq. inches

that is your answer

5 0

3 years ago

the 7th grade class plans to collect at least 600 pairs of socks for people in need. so far, 135 pairs have been collected. how

polet [3.4K]

Answer:

465 Socks.

Step-by-step explanation:

600 - 135 = 465

7 0

3 years ago

Read 2 more answers