Function 1 has a maximum at y = 1
Now we need to find the maximum of Function 2 by completing the square:
-x^2 + 2x - 3
= -(x^2 - 2x) - 3
= -(x - 1)^2 +1 - 3
= -(x - 1)^2 - 2
Therefor the turning point is at (1, -2) and the maximum is at y = -2
-2 < 1, therefor Function 1 has the larger maximum
110 is the answer to that
(<span>−v</span>)<span>(p)</span>+40<95
−<span>pv</span>+40+<span>−40</span><<span>95+<span>−40</span></span>
−<span>pv</span><<span>55</span>
<span>-pv/-p < 55/-p</span>
<span>v > -55/p</span>
<span> your final answer is -55/p</span>
Yes they are! The square root of 36 is 6 and the square root of 25 is 5.
Let the nomber of 2 pointers be x and that of 3 pointers be y, then
2x + 3y = 30 . . . (1)
x = y + 5 . . . (2)
Putting (2) into (1), gives 2(y + 5) + 3y = 30
2y + 10 + 3y = 30
5y = 30 - 10 = 20
y = 20/5 = 4
x = 4 + 5 = 9
