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Tju [1.3M]
3 years ago
13

George invests $2000 in an account with an interest rate of 5%. Which best represents this?

Mathematics
1 answer:
777dan777 [17]3 years ago
6 0

Answer:

Y=2000(1.05)^x

Step-by-step explanation:

This is because 2000 is the fixed beginning value and should stay by itself.

While the interest rate of 5% is 1.05 because the amount of money George will have will be going up based on the fixed beginning value.

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an octagonal prism has 8 lateral faces

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On a quiz there are four multiple-choice questions worth 3 points each and two true/false questions worth 1 point each. Each mul
Pani-rosa [81]

Answer: Expected value would be \dfrac{17}{5}

Step-by-step explanation:

Since we have given that

Number of multiple choice question = 4

Number of true false questions = 2

Number of points for each multiple choice question = 3

Number of points for each true false question = 1

Number of choices in multiple choice = 5

Probability of getting correct answer in multiple choice question = \dfrac{1}{5}

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Expected value of the student's score on the test would be

E(x)=\sum xp(x)\\\\E(x)=4\times 3\times \dfrac{1}{5}+2\times 1\times \dfrac{1}{2}\\\\E(x)=\dfrac{12}{5}+1\\\\E(x)=\dfrac{12+5}{5}=\dfrac{17}{5}

Hence, expected value would be \dfrac{17}{5}

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Let X equal the number of flips of a fair coin that are required to observe
Nataliya [291]

Answer:

(a) I attached a photo with the diagram.

(b) f(x) = \big( \frac{1}{2} \big)^{x-1}

(c) 1/4

(d) 4

(e) k^2/2

Step-by-step explanation:

(a) I attached a photo with the diagram.

(b) The easiest way to think about this part is in terms of combinatorics. Think about it like this.

To begin with, look at the three each level of the three represents a possible outcome of throwing the coin n-times. If you throw the coin 3 times at the end in total there are 8 possible outcomes. But The favorable outcomes are just 2.

 1  - Your first outcome is HEADS and all the others are different except the last one.

 2  - Your first outcome is TAILS and all the others are different except the last one.

Therefore the probability of the event is

f(x) = P(X=x) = \frac{2}{2^x}  = \frac{1}{2^{x-1}} = \big( \frac{1}{2} \big)^{x-1}

(c)

P(X = 0) = 0 because it is not possible to have two consecutive tails or heads.

E(X > 4) = 1 - P(X \leq 3) = 1 - ( P(X = 0 ) + P(X = 1) + P(X = 2) + P(X = 3))\\= 1 - ( \frac{1}{2} + \frac{1}{4} ) = \frac{1}{4}

(d)

Remember that this is a geometric distribution therefore

E[X] = p/(1-p), in this case  p = 1/2 so E[X] = 1 and

E[X+1]^2 = ( E[X] +1 )^2  = (1+1)^2 = 2^2 = 4

Also

(e)

This is a geometric distribution so its variance is

Var(X) = \frac{1-p}{p^2} = 1/2 / 1/4 = 1/2

And using properties of variance

Var(kX - k ) = Var(kX) = k^2 var(X) = k^2 /2

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4 years ago
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