Answer:
the answer is 48, or the second choice B
Step-by-step explanation:
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
We have an equation: 56/? = 4/100
Cross multiply:
4*? = 56*100
⇒ ? = 56*100/4
⇒ ?= 1,400
4% of 1,400 days is 56 days~
Answer:
35 plants
Step-by-step explanation:
For this case we can make the following rule of three:
4 gallons --------------> 14 plants
x --------------------------> 35 plants
From here, we clear the value of x.
We have then:
therefore, 10 gallons are needed to irrigate 35 plants.
Answer:
it will take 10 gallons to water 35 plants
Answer:
I believe it is 9
Step-by-step explanation:
alls I did was add the adults to the students then I divide 375 by 44 I got a weird decimal so I rounded it up to 9
