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DENIUS [597]
3 years ago
10

Which equation can be used to find the unknown length, b, in this triangle?​

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

use pythagorean theorem

Step-by-step explanation:

a^2+b^2=c^2

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1/2 =4/ Please help
Dennis_Churaev [7]
1/2 = 2/4 because if you divide 2/4 by 2 you get 1/2. 
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3 years ago
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The "Double-R-7" Ranch has a new owner. The 20 animals, all hummingbirds and mice, are dismayed, as they have heard that he is b
topjm [15]
H+M=20
2H+4M=64 the 2 because hummingbirds have 2 feet and the 4 because mice have 4 feet
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3 years ago
If x = 8.1, then y = 2.7. Find x when y = 5.4.
shusha [124]

Answer by JKismyhusbandbae: 16.2

All you do is add the same number every-time.

2.7 + 2.7 to get 5.4.

8.1 + 8.1 to get 16.2

If you wanted to find y again 5.4 + 5.4 = 10.8.

3 0
4 years ago
A 500 gallon tank initially contains 200 gallons of water with 5 lbs of salt dissolved in it. Water enters the tank at a rate of
Lapatulllka [165]
Until the concerns I raised in the comments are resolved, you can still set up the differential equation that gives the amount of salt within the tank over time. Call it A(t).

Then the ODE representing the change in the amount of salt over time is

\dfrac{\mathrm dA}{\mathrm dt}=\text{rate in}-\text{rate out}
\dfrac{\mathrm dA}{\mathrm dt}=\dfrac{2\text{ gal}}{1\text{ hr}}\times\dfrac{\frac15(1+\cos t)\text{ lbs}}{1\text{ gal}}-\dfrac{2\text{ gal}}{1\text{ hr}}\times\dfrac{A(t)\text{ lbs}}{500+(2-2)t}
\dfrac{\mathrm dA}{\mathrm dt}=\dfrac25(1+\cos t)-\dfrac1{250}A(t)

and this with the initial condition A(0)=5

You have

\dfrac{\mathrm dA}{\mathrm dt}+\dfrac1{250}A(t)=\dfrac25(1+\cos t)
e^{t/250}\dfrac{\mathrm dA}{\mathrm dt}+\dfrac1{250}e^{t/250}A(t)=\dfrac25e^{t/250}(1+\cos t)
\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/250}A(t)\right]=\dfrac25e^{t/250}(1+\cos t)

Integrating both sides gives

e^{t/250}A(t)=100e^{t/250}\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)+C
A(t)=100\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)+Ce^{-t/250}

Since A(0)=5, you get

5=100\left(1+\dfrac1{62501}\right)+C\implies C=-\dfrac{5937695}{62501}

so the amount of salt at any given time in the tank is

A(t)=100\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)-\dfrac{5937695}{62501}e^{-t/250}

The tank will never overflow, since the same amount of solution flows into the tank as it does out of the tank, so with the given conditions it's not possible to answer the question.

However, you can make some observations about end behavior. As t\to\infty, the exponential term vanishes and the amount of salt in the tank will oscillate between a maximum of about 100.4 lbs and a minimum of 99.6 lbs.
5 0
4 years ago
A box contains 5 blue pens and three black pens you chosse one pen at random do not replace it and then choose a second pen at r
Anuta_ua [19.1K]

Answer:

4

Step-by-step explanation:

U will add 5 plus 3 and then divide 8 by 2

3 0
3 years ago
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