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ivann1987 [24]
3 years ago
7

The line AB had midpoint (2, 5).A has coordinates (1, 2).Find the coordinates of B.

Mathematics
2 answers:
sveta [45]3 years ago
5 0

Answer:

The line AB, with A(Ax, Ay), B(Bx, By) and midpoint M(Mx, My) satisfying:

Ax + Bx = 2Mx

Ay + By = 2My

=>

2 + Bx = 2*1

5 + By = 2*2

=> Bx = 0

=> By = -1

=> B(0, -1)

Hope this helps!

:)

blagie [28]3 years ago
4 0

Answer:

B(3, 8 )

Step-by-step explanation:

Using the midpoint formula

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then midpoint is

[ \frac{1}{2}(x₁ + x₂ ), \frac{1}{2}(y₁ + y₂ ) ]

let the coordinates of B = (x, y ), then

\frac{1}{2}(1 + x) = 2 ( multiply both sides by 2 )

1 + x = 4 ( subtract 1 from both sides )

x = 3

and

\frac{1}{2} (2 + y) = 5 ( multiply both sides by 2 )

2 + y = 10 ( subtract 2 from both sides )

y = 8

Thus

coordinates of B = (3, 8 )

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3 years ago
Solve for u. u+1/4=-4/5
DedPeter [7]

Answer:

u = (-21)/20

Step-by-step explanation:

Solve for u:

u + 1/4 = (-4)/5

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(4 u)/4 + 1/4 = -4/5

(4 u)/4 + 1/4 = (4 u + 1)/4:

1/4 (4 u + 1) = -4/5

Multiply both sides of (4 u + 1)/4 = (-4)/5 by 4:

(4 (4 u + 1))/4 = (-4)/5×4

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(4 (4 u + 1))/4 = (-4×4)/5

(4 (4 u + 1))/4 = 4/4×(4 u + 1) = 4 u + 1:

4 u + 1 = (-4×4)/5

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4 u + 1 = (-16)/5

Subtract 1 from both sides:

4 u + (1 - 1) = (-16)/5 - 1

1 - 1 = 0:

4 u = (-16)/5 - 1

Put (-16)/5 - 1 over the common denominator 5. (-16)/5 - 1 = (-16)/5 - 5/5:

4 u = (-16)/5 - 5/5

-16/5 - 5/5 = (-16 - 5)/5:

4 u = (-16 - 5)/5

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4 u = (-21)/5

Divide both sides by 4:

u = ((-21)/4)/5

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Answer:  u = (-21)/20

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3 years ago
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3 years ago
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Answer:

A. 44.82%

B.

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C.

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Using this formula

Return on equity = The Net income amount /The Average stockholders' equity amount

Let plug in the formula

Return on equity=2,634.4/[(5,605+6,151)/2]

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6 0
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HELPPPP<br> What is MB<br><br><br> 48<br> 96<br> 110<br> 55
Lady_Fox [76]
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As indicated in the hints,
OA=OC  => OAC=OCA=(180-110)/2 = 35
Similarly,
OAB=OBA=(48-35)=13
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=>
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Check:
55+55+35+35+13+13 = 180 degrees (angles of a triangle)  ok.

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