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3 years ago

It is asking what is the relationship between segment pq and p”q’

Mathematics

1 answer:

nadezda [96]3 years ago

7 0

angles it sounds like but ik the struggle

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A class of 33 students elected a class treasurer. There were 11 votes for Candidate A and 15 votes for Candidate B. The remainin

vovangra [49]

To start out, notice that you want the percent of voters that chose candidate A, not the percent of the class that chose candidate A.

Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying:
"number that chose candidate A" divided by "number of voters"

1) The numerator of the fraction should be the number of votes for candidate A, which is 11.

2) The denominator of the fraction should be the number of voters. You're told that "there were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
 $11 + 15 \: total \: votes$

3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
$\frac{11}{11+15} \times 100$

----

Answer: Top right choice, $\frac{11}{11+15} \times 100$

5 0

2 years ago

Combining Like Terms

swat32

It would be a + because the 7 in 7y is positive, therefore it would be added to the X’s. if it was -7y, then the underline would be a –.

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2 years ago

3044 in a base 5 to a base 10

nikklg [1K]

3,059 I don’t really care

4 0

2 years ago

Please help It’s almost due

Tems11 [23]

Answer:

10 people

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base

kaheart [24]

Answer:

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

We expect your answer is supposed to be Step 4.

7 0

3 years ago