Answer:
B) 10 microJoule
Explanation:
Given
v = 100 micrometer/s
F = 0.1 N
t = 1 s
we get the displacement as follows
d = v*t ⇒ d = (100 micrometer/s)*(1 s) = 100 micrometer
then we apply the formula
W = F*d*Cos ∅
⇒ W = (0.1 N)*(100 micrometer)*Cos 0°
⇒ W = 10 microJoule
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Answer:
The value is
Explanation:
From the question we are told that
The frequency of the second player is
The beat frequency is
The speed of sound is
Generally the frequency of the note played by the first player is mathematically represented as
=>
=>
From the relation of Doppler Shift we have that
Here
So
=>
Answer:
Explanation:
Work function of aluminium is 4.1 eV .
Therefor light of minimum energy of 4.1 eV will be required to cause the emission of electrons.
If we use this frequency of light or energy of light to effect ejection of photoelectrons from cesium , it will be easily ejected because energy requirement for this metal is lower ( work function is lower 2.1 eV ). than the energy of photon falling on it.
If we use this frequency of light or energy of light to effect ejection of photoelectrons from aluminium , it will be not ejected because energy requirement for this metal is high ( work function is higher 5.1 eV ) . Even if we increase the intensity of light , electrons will not be ejected because energy of each photon depends upon the frequency .