Question

Three hunters x,y and z aim at a bird on top of a tree.Their individual probabilities of killing the bird are 3/5,2/3 and 5/6 respectively.Find the probability that 1. Only x and y kill the bird 2. Only two of them kill the bird 3. Only 2 kill the bird 4. Only one of them kill the bird 5. None of them kill the bird 6. All of them kill the bird

Answer 1

Answer:

1   3/5*2/3=6/15

2   (3/5*2/3)+(2/3*5/6)+(3/5*5/6)=Ans

3  same as 2 i think

4  3/5+2/3+5/6=ans

5 (1-3/5)*(1-2/3)*(1-5/6)

Explanation

1 means x and y... for such a  we multiply the probabilities

2 means x and y or x and z or y and z9 multiply ands  add ors

3 i think it is same as 2

4 for this you have to negate the probabilities of killing to find that of not killing.   Since it will be x and y and z, you multiply the final probabilities

:)