Question

A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed.

Answer 1

Hello!

A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed.

We have the following data:

* velocity (in mph)

(V1) = 35.0 mph

(V2) = 40.0 mph

(V3) = 50.0 mph

* weights for the time (in hours)

(T1) = 1.00 hour

(T2) = 0.0500 hour

(T3) = 2.00 hours

We apply the data to the weighted average formula to find the average speed, let us see:

$Weight\:Average = \dfrac{V_1*T_1+V_2*T_2+V_3*T_3}{T_1+T_2+T_3}$

$Weight\:Average = \dfrac{35.0*1.00+40.0*0.0500+50.0*2.00}{1.00+0.0500+2.00}$

$Weight\:Average = \dfrac{35+2+100}{3.05}$

$Weight\:Average = \dfrac{137}{3.05}$

$Weight\:Average = 44.91803279...$

$\boxed{\boxed{Weight\:Average = 44.92\:mph}}\Longleftarrow(Average\:Speed)\:\:\:\:\:\:\bf\purple{\checkmark}$

Answer:

The Average Speed is approximately 44.92 mph

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$\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

Answer 2

Answer:

Average speed will be $44.91mile/hour$

Explanation:

We have given that car travels 35 mph for 1 hour in north

So distance traveled by car in north = 35×1=35 mile

Car travels 40 mph in east for 0.05 hour

So distance traveled in east = 40×0.05 = 2 mile

And finally the car travels at 50 mph for 2 hour in northeast

So distance traveled in northeast = 50×2 = 100 mile

So total distance = 35+2+100 = 137 mile

Total time = 1+0.05+2=3.05 hour

Now we know that average speed is given by $speed=\frac{total\ distance}{total\ time }=\frac{137}{3.05}=44.91mile/hour$