Sugar molecules can be oxidized in the cells of animals. This oxidation releases energy for the animal to use. From what source
2 answers:
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Answer:
Phenotypic ratio: 1:4:6:4:1
Punnett square: Below in the explanation box
Frequency distribution: In the attached files
Explanation:
<u>Available data</u>:
- The kernel color in wheat is a continuous trait determined by two additive diallelic genes
- The red kernels are determined by two genes and two dominant alleles (R1R1R2R2)
- The white kernels are determined by two recessive alleles at the same two genes (r1r1r2r2)
- R1 and R2 alleles are dominant over r1 and r2, respectively
1st Cross: a true-breeding red plant with a true-breeding white plant
Parentals) R1R1R2R2 x r1r1r2r2
Gametes) R1R2, R1R2, R1R2, R1R2
r1r2, r1r2, r1r2, r1r2
F1) 100% R1r1R2r2
2nd Cross: F1 progeny are selfed
Parentals) R1r1R2r2 x R1r1R2r2
Gametes) R1R2, R1r2, r1R2, r1r2
R1R2, R1r2, r1R2, r1r2
Punnett square) R1R2 R1r2 r1R2 r1r2
R1R2 R1R1R2R2 R1R1R2r2 R1r1R2R2 R1r1R2r2
R1r2 R1R1R2r2 R1R1r2r2 R1r1R2R2 R1r1R2r2
r1R2 R1r1R2R2 R1r1R2r2 r1r1R2R2 r1r1R2r2
r1r2 R1r1R2r2 R1r1r2r2 r1r1R2r2 r1r1r2r2
F2) Genotype:
- 1/16 R1R1R2R2 (dark red)
- 2/16 R1R1R2r2 (red)
- 1/16 R1R1r2r2 (light red)
- 2/16 R1r1R2R2 (red)
- 4/16 R1r1R2r2 (light red)
- 2/16 R1r1r2r2 (very light red)
- 1/16 r1r1R2R2 (light red)
- 2/16r1r1R2r2 (very light red)
- 1/16 r1r1r2r2 (white)
Phenotype:
- 1/16 R1 R1 R2R2, dark red phenotype
- 4/16 R1r1R2R2 + R1R1Rr2, red phenotype
- 6/16 R1r1 R2r2 + r1r1R2R2 + R1R1r2r2, light red phenotype
- 4/16 R1r1 r2r2 + r1r1R2r2, very light red phenotype
- 1/16 r1r1r2r2, White phenotype phenotype
Phenotypic ratio: 1:4:6:4:1
Frequency table:
<u>DOSAGE FREQUENCY</u>
Dark red 1/16
Red 4/16
Light red 6/16
Very light red 4/16
White 1/16
