System of equations, special case infinitely many solutions?????
1 answer:
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Answer:
- ∠CDE ↔ 50°
- ∠FEG ↔ 75°
- ∠ACB ↔ 55°
Step-by-step explanation:
To solve angle problems like this, you make use of three relations:
- linear angles have a sum of 180°
- angles in a triangle have a sum of 180°
- vertical angles have the same measure
The attached diagram shows the measures of all of the angles of interest in the figure. The ones shown in blue are the ones that have the measures and names on the list of answer choices.
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A good place to start is with the linear angle pair at A. Since the sum of the two angles is 180°, the angle at A that is inside the triangle will be ...
180° -130° = 50°
Then the missing angle in that triangle at C will have the measure that makes the sum of triangle angles be 180°:
∠ACB = 180° -50° -75° = 55° . . . . . this is one of the angles on your list
Similarly, the angle at E inside triangle FEG will have a measure that makes those angles have a sum of 180°:
∠FEG = 180° -60° -45° = 75° . . . . . this is one of the angles on your list
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The two angles whose measures we just found are vertical angles with the base angles in triangle CDE, so that triangle's angle D will have a measure that makes the total be 180°.
∠CDE = 180° -55° -75° = 50° . . . . . this is one of the angles on your list
9514 1404 393
Answer:
22
Step-by-step explanation:
Put -3 where x is and do the arithmetic.
f(-3) = 3(-3)² -2(-3) -11 = 27 +6 -11
f(-3) = 22
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<em>Additional comment</em>
Sometimes evaluation is easier if you rewrite the polynomial in Horner form:
f(x) = (3x -2)x -11
f(-3) = (3(-3) -2)(-3) -11 = -11(-3) -11 = 33 -11 = 22
