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NeTakaya
3 years ago
10

System of equations, special case infinitely many solutions?????

Mathematics
1 answer:
Mashcka [7]3 years ago
4 0

One possible system is

1x + 3y = 4

2x + 6y = 8

Note how 2 is twice as large as 1, 6 is twice as large as 3, and 8 is twice as large as 4.

In other words, the second equation is the result of multiplying both sides of the first equation by 2.

1x+3y = 4

2*(1x+3y) = 2*4

2x+6y = 8

Effectively the two equations in bold are the same which produces the same line. The two lines overlap perfectly to intersect infinitely many times. An intersection is a solution.

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Simplify the given algebraic expression.<br> 8(5y - 8) - (5y + 3)
RoseWind [281]

Answer:

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Step-by-step explanation:

8(5y - 8) - (5y + 3)

Multiply the 8 with what is in the parentheses.

40y - 64 - 5y + 3

Subtract like terms.

35y - 67

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A sum of money amounting to $4.15 consists of dimes and quarters. If there are 28
anastassius [24]

Answer:

there are 9 quarters and 19 dimes

Step-by-step explanation:

Let x be the number of dimes and y the number of quarters

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=> x = 28 - y

We have the equation:

0.25y + 0.1x = 4.15

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