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3 years ago

How is it possible for a protein to change over 70% of its amino acids and still fold in the same way?

Chemistry

1 answer:

Varvara68 [4.7K]3 years ago

5 0

The complete question is

Comparison of a homeodomain protein from yeast and Drosophila shows that only 17 of its 60 amino acids are identical. How is it possible for a protein to change over 70% of its amino acids and still fold in the same way?

Answer:

Many different strings of the amino acid can give rise to the identical protein folds. The amino acid differences between the Drosophila and homeodomain proteins from yeast are the functional proteins which do not change their structure and function.

There is a several amount of folding required which can cause change in the protein structure.

There is a basic functional proteins common in both the organism which do not change its structure and function.

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Answer:

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3 years ago

When a piece of solid phosphorus is added to a flask containing chlorine gas, heat is evolved?

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3 years ago

A student gains 1.0 lb in two weeks. How many grams did he gain?

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3 years ago

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Lyrx [107]

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Explanation:

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3 years ago

Calculate the mass of iron(III) oxide that contains a million iron atoms. Be sure your answer has a unit symbol if necessary, an

KiRa [710]

<u>Answer:</u> The mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

<u>Explanation:</u>

We are given:

Number of iron atoms = A million = $1.0\times 10^6$

The chemical formula of the given compound is $Fe_2O_3$

It is formed by the combination of 2 iron atoms and 3 oxygen atoms.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

1 mole of iron (II) oxide will contain = $(2\times 6.022\times 10^{23})=1.2044\times 10^{24}$ number of iron atoms

We know that:

Molar mass of iron (II) oxide = 159.7 g/mol

Applying unitary method:

For $1.2044\times 10^{24}$ number of iron atoms, the mass of iron (II) oxide is 159.7 g

So, for $1.0\times 10^6$ number of iron atoms, the mass of iron (II) oxide will be $\frac{159.7}{1.2044\times 10^{24}}\times 1.0\times 10^6=2.6\times 10^{-17}g$

Hence, the mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

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4 years ago