Answer:
Sodium is a very reactive metal, it tends to react with oxygen to form sodium oxide but this is an unstable compound and soon reacts with hydrogen to form sodium hydroxide. Sodium is the metal reacts vigorously with oxygen and water.
4 Na + O2 → 2 Na2O.
Answer:
(C)Calcium oxide reacts sulfuric acid
Explanation:
Oxygen and glucose that’s all I know
Answer:
The new pressure is 1.05 atm
Explanation:
Step 1: Data given
Number of moles oxygen gas = 6.2 moles
Volume of the cylinder = 4.3 L
Pressure of the gas = 3.8 atm
The volume changed to 15.5 L
Step 2: Calculate the new pressure
P1*V1 = P2*V2
⇒with P1 = the initial pressure of the gas = 3.8 atm
⇒with V1 = the initial volume = 4.3 L
⇒with V2 = the increased volume = 15.5 L
⇒with P2 = the new pressure = TO BE DETERMINED
3.8 atm * 4.3 L = 15.5 L * P2
P2 = (3.8 atm *4.3 L) / 15.5 L
P2 = 1.05 atm
The new pressure is 1.05 atm
Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
![\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bn%5Ctimes%20H_f_%7Bproducts%7D%5D-%5Bn%5Ctimes%20H_f_%7Breactants%7D%5D)
Putting the values we get :
![\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B8%5Ctimes%20H_f_%7BCO_2%7D%2B10%5Ctimes%20H_f_%7BH_2O%7D%5D-%5B2%5Ctimes%20H_f_%7BC_4H_%7B10%7D%2B13%5Ctimes%20H_f_%7BO_2%7D%7D%5D)
![\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%288%5Ctimes%20-393.5%29%2B%2810%5Ctimes%20-241.82%29%5D-%5B%282%5Ctimes%20-125.7%29%2B%2813%5Ctimes%200%29%5D)
2 moles of butane releases heat = 5314.8 kJ
1 mole of butane release heat = 
Thus enthalpy of combustion per mole of butane is -2657.4 kJ
