Answer:
No se ingles te ayudaria pero no entiendo nada
<u>Answer:</u> The empirical and molecular formula of the compound is and respectively
<u>Explanation:</u>
We are given:
Mass of C = 3.758 g
Mass of H = 0.316 g
Mass of O = 1.251 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Moles of Oxygen =
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.
For Carbon =
For Hydrogen =
For Oxygen =
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of C : H : O = 4 : 4 : 1
The empirical formula for the given compound is
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is:
We are given:
Mass of molecular formula = 130 g/mol
Mass of empirical formula = 68 g/mol
Putting values in above equation, we get:
Multiplying this valency by the subscript of every element of empirical formula, we get:
Hence, the empirical and molecular formula of the compound is and respectively
Explanation:
As density is defined as the mass of a substance divided by its volume.
Mathematically, Density =
It is given that mass is 50 g and density is 0.934 .
Hence, calculate the volume of methyl acetate as follows.
Density =
0.934 =
Volume =
or, = (as 1 = 1 mL)
Thus, we can conclude that the volume of methyl acetate the student should pour out is .
1 Hydrogen 1s1
2 Helium 1s2
3 Lithium 2s1