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4 years ago

Please help!! Chemistry!! Important!! Will mark brainiliest

Chemistry

1 answer:

slega [8]4 years ago

4 0

<h2>Answer:</h2><h3>Part 1 :</h3>

The option B is correct option.

The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing OH- ions.

<h3>Explanation:</h3>

Full equation:

2MnO2 + H2O + 2e- → Mn2O3 + 2OH-

The oxidation number of S in SO2−4 is 0.

Because in ionic compounds sum of oxidation number is equal to charge.

If compound is SO4-2 then option d will correct option.

Because (+6) + (-2 * 4) = -2

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In which type of bond are electrons shared equally between two atoms?

Natali5045456 [20]

Answer:

Nonpolar Covalent Bond

Explanation:

A nonpolar covalent bond is one in which the bonding electrons are evenly distributed between the two atoms.

Good Luck!

Hope this helps!

6 0

3 years ago

The pressure of 1 mol of gas is decreased to 0.5 atm at 273 K. What happens to the molar volume of the gas under these condition

m_a_m_a [10]

Answer : The molar volume of the gas will be, 44.82 L

Solution :

Using ideal gas equation,

$PV=nRT$

where,

n = number of moles of gas = 1 mole

P = pressure of the gas = 0.5 atm

T = temperature of the gas = 273 K

R = gas constant = 0.0821 Latm/moleK

V = volume of the gas.

Now put all the given values in the above equation, we get the molar volume of the gas.

$(0.5atm)\times V=(1mole)\times (0.0821Latm/moleK)\times (273K)$

$V=44.82L$

Therefore, the molar volume of the gas will be, 44.82 L

6 0

3 years ago

The black, granular material that fills a dry cell in a common flashlight (between the carbon rod and the zinc shell) is mangane

mestny [16]

Answer: c. +4

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

$Mn:25:1s^22s^22p^63s^23p^64s^23d^{5}$

$Mn^{4+}:21:1s^22s^22p^63s^23p^63d^1$

$O:8:1s^22s^22p^4$

$O^{2-}:10:1s^22s^22p^6$

Here manganese is having an oxidation state of +4 called as cation and oxygen forms an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged to give $Mn_2O_4$ which written in simplest whole number ratios to give neutral $MnO_2$