Answer:
7, -3/4, -3
Step-by-step explanation:
Note that all three of the given functions are linear. We can read the slopes directly from these functions: 7, -3/4, -3. Between any two values of x, the slope is exactly the same in each of these three functions.
Thus,
1) the average rate of change of f(x) = 7x - 4 over the interval [2,4] is 7.
2) the average rate of change of g(x) over the given interval is -3/4.
3) the average rate of change of h(x) over the given interval is -3.
You need to divide this problem into two parts
first part is when it was accelerating.. that time use the equation of motion and calculate what is the total angle covered and hence you get the number of revolutions
then find the time of acceleration..so you ll understand for how much did you do the above calculation
for the rest of the time, the speed is constant (final angular speed).. so now you just use
w= theta/ time.. and get theta and again calculate the number of revolutions!
The volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
<h3>What is the volume of right square pyramid?</h3>
The volume of a square pyramid is expressed as;
V = (1/3)a²h
Where a is the base length and h is the height of the pyramid
Given that;
- Base edges of the square base a = 64cm
- Slant height s = 40cm
- Height of the pyramid h = ?
- Volume = ?
First, we determine the height of the pyramid using Pythagorean theorem.
c² = a² + b²
- c = s = 40cm
- a = half of the base length = a/2 = 64cm/2 = 32cm
- b = h
(40cm) = (32cm)² + h²
1600cm² = 1024cm² + h²
h² = 1600cm² - 1024cm²
h² = 576cm²
h = √576cm²
h = 24cm
Now, we calculate the volume of the right square pyramid;
V = (1/3)a²h
V = (1/3) × (64cm)² × 24cm
V = (1/3) × 409664cm² × 24cm
V = 32768cm³
Therefore, the volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
Learn more about volume of pyramids here: brainly.com/question/27666514
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2.45 is exactly in between 2.4 and 2.5
In parallelogram opposite angles are congruent,
∠1=∠2
Consecutive angles are supplementary
62°+m∠1=180°
m∠1= 180-62= 118°
m∠1+m∠2=m∠1+m∠1=118°+118°=236°
