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expeople1 [14]
3 years ago
13

Graph the relation. Is the relation a function? Why or why not? {(–1, 1), (–2, 1), (–2, 2), (0, 2)} Yes; there is only one domai

n value for each range value. No; a domain value has two range values. Yes; there is only one range value for each domain value. No; a range value has two domain values.
Mathematics
1 answer:
Luden [163]3 years ago
7 0

{(–1, 1), (–2, 1), (–2, 2), (0, 2)}

In a function, each input has an output

Each domain has a range. In a function, range can be repeated but domain cannot be repeated. Same domain cannot have two range values.

Here domain is {-1, -2, -2, 0}

Range is { 1, 1, 2, 2}

Domain -2 is repeating so this relation is not a function

Answer : No; a domain value has two range values.


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5n+2 (11-7n)=12+4 (n-4)
Inessa05 [86]
Does that make sense?
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3 years ago
Find the equation of a circle that has a diameter with the endpoints given by the points A(-4,9) and B (- 2, - 3) )
Aleksandr-060686 [28]

The equation of the circle is (x+3)^{2}+(y-3)^{2}=37

Explanation:

Given that the endpoints of the circle are A(-4,9) and B(-2,-3)

We need to determine the equation of the circle.

<u>Center:</u>

The center of the circle can be determined using the midpoint formula,

Center=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates A(-4,9) and B(-2,-3), we get,

Center=(\frac{-4-2}{2},\frac{9-3}{2})

Center=(\frac{-6}{2},\frac{6}{2})

Center=(-3,3)

Thus, the center of the circle is (-3,3)

<u>Radius:</u>

The radius of the circle can be determined using the distance formula,

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Substituting the center (-3,3) and the endpoint (-4,9), we get,

r=\sqrt{\left(-4+3\right)^{2}+\left(9-3\right)^{2}}

r=\sqrt{\left(-1\right)^{2}+\left(6\right)^{2}}

r=\sqrt{1+36}

r=\sqrt{37}

Thus, the radius of the circle is \sqrt{37}

<u>Equation of the circle:</u>

The standard form of the equation of the circle is given by

(x-a)^{2}+(y-b)^{2}=r^{2}

where (a,b) is the center and r is the radius.

Substituting the values, we have,

(x+3)^{2}+(y-3)^{2}=(\sqrt{37})^{2}

(x+3)^{2}+(y-3)^{2}=37

Thus, the equation of the circle is (x+3)^{2}+(y-3)^{2}=37

7 0
3 years ago
Brayden is simplifying the expression 4n – (n – 3)2. He begins by distributing the negative to the terms inside the parentheses.
RoseWind [281]
The right approach would be:
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The options confused me. So pick the answer based on the solution.
7 0
3 years ago
Read 2 more answers
Simplify: answer in the box
leva [86]

Answer:

I got 24x^2  over x^2+7x+10

Step-by-step explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

7 0
3 years ago
When baking a cake, you have a choice of the following pans: a round cake pan that is 2 inches deep and has a 7 inch diameter a
ruslelena [56]
Round pan volume is:
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The icing that will be needed to frost the round cake pan is:
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Icing that will be needed for the rec. cake pan is:

2•9•2=36 in^2
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6•2= 12 in^2
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Good luck ;-)

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3 years ago
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