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2 years ago

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Graph the relation. Is the relation a function? Why or why not? {(–1, 1), (–2, 1), (–2, 2), (0, 2)} Yes; there is only one domai

n value for each range value. No; a domain value has two range values. Yes; there is only one range value for each domain value. No; a range value has two domain values.

1 answer:

Luden [163]2 years ago

7 0

{(–1, 1), (–2, 1), (–2, 2), (0, 2)}

In a function, each input has an output

Each domain has a range. In a function, range can be repeated but domain cannot be repeated. Same domain cannot have two range values.

Here domain is {-1, -2, -2, 0}

Range is { 1, 1, 2, 2}

Domain -2 is repeating so this relation is not a function

Answer : No; a domain value has two range values.

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The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO

Margarita [4]

Answer:

$\angle PRQ = 80$

Step-by-step explanation:

Given

$\angle SPR = 145^o$

$\angle POT = 115^o$

See attachment

Required

Find $\angle PRO$

First, calculate $\angle RPO$

$\angle RPO + \angle SPR = 180$ --- angle on a straight line

So, we have:

$\angle RPO + 145 = 180$

Collect like terms

$\angle RPO = 180 - 145$

$\angle RPO = 35$

Next, calculate PQR

$\angle POR + \angle POT = 180$

So, we have:

$\angle POR + 115 = 180$

Collect like terms

$\angle POR = 180-115$

$\angle POR = 65$

So, PRO is calculated as:

$\angle PRO + \angle POR + \angle RPO = 180$ --- angles in a triangle

So, we have:

$\angle PRO + 65 + 35= 180$

$\angle PRO + 100= 180$

Collect like terms

$\angle PRO = 180-100$

$\angle PRO = 80$

3 0

2 years ago

Sin a_____=1/2 [sin (a + b) + sin (a - b)]

QveST [7]

Answer:

$\textbf{A.} \cos b$

Step-by-step explanation:

$\dfrac 12 \left[\sin(a+b)+\sin(a-b) \right]\\\\\\=\dfrac 12\left[ 2 \sin a \cos b\right]\\\\\\=\sin a \cos b$

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1 year ago

Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write

Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

Use double point formula and simplify it to get two eqaution.
Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)$

~ Keep all values.

$(y + 4) = \frac{11 + 4}{2 + 1} (x + 1)$

~ Simplify it.

$y + 4 = \frac{15}{3} (x + 1)$

$y + 4 = 5x + 5$

$5x - y + 1 = 0$

Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1)$

~ Keep all values.

$(y - 1) = \frac{10 - 1}{4 - 1} (x - 1)$

~ Simplify it.

$y - 1 = 3 x - 3$

$3x - y - 2 = 0$

Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

$m1 = \frac{ - coeff. \: of \: x}{coeff \: of \: y}$

$m1 = \frac{ - 5}{ - 1}$

Therefore, m1 = 5

Slope of second equation.

$m2 = \frac{ - coeff \: .of \: x}{coeff \: .of \: y}$

$m2 = \frac{ - 3}{ - 1}$

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

3*5≠-1.

Therefore, they aren't perpendicular too.

So, they are neither.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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2 years ago

Solve (x +1 < 4) n ( x - 8 > -7)?

Anna007 [38]

X<3 or X>1

move constant to the right side and change the sign

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James' little brother has a plastic box in the shape of a rectangular prism. The plastic box is 912 inches long, 512 inches wide

Anna35 [415]

Multiply 912 x 512 x 3 = ? then divide your answer by 12 .

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