2 years ago

Write the exponential equation 3^7=2137 ad a logartithmic function

1 answer:

7 0

The formula is b^x=a is the same as log{b}a=x. So in your problem b=3, x=7 and a=2137. Then you plug it into the log part of the equation. log(3)2137=7.

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A linear function is graphed below.

Evgen [1.6K]

Answer:

$-1\frac{1}{2}$

Step-by-step explanation:

We have two coordinate points and are asked to find a slope.

When finding slope, we can use the formula listed :

$\frac{y^2-y^1}{x^2-x^1}}$

To understand what the variables are, you can take this :

$(x^1,y^1)$

$(x^2,y^2)$

Substitute the points :

$(-1,4)$

$(5,-5)$

Now substitute it into the formula :

$\frac{-5-4}{5-(-1)}$

$\frac{-3}{2}$

$-1\frac{1}{2}$

4 0

2 years ago

Read 2 more answers

Evaluate S5 for 400 + 200 + 100 + … and select the correct answer below.

Nadusha1986 [10]

The correct answer is B) 775

Why 775? Because Assume the series continues.

400+200+100+50+25=775

I hope this helps.

Have a great day. :)

5 0

2 years ago

Read 2 more answers

Work out 5/8 x 2 please help quick

Fed [463]

5/8 * 2 =

10/8 =

5/4
-------------------

your answer is 5/4

4 0

2 years ago

Photo Provided... 25+ Points Provided...

viktelen [127]

Answer:

1) 2 units right

2) 2 units up

3) 2 units left

4) 2 units down

7 0

2 years ago

Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√

TiliK225 [7]

Parameterize the part of the sphere by

$\mathbf s(u,v)=(9\cos u\sin v,9\sin u\sin v,9\cos v)$

with $0\le u\le2\pi$ and $0\le v\le\dfrac\pi4$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv$

So the area of $S$ (the part of the sphere above the cone) is given by

$\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi$

4 0

3 years ago