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marysya [2.9K]
3 years ago
10

Write the exponential equation 3^7=2137 ad a logartithmic function

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0
The formula is b^x=a is the same as log{b}a=x. So in your problem b=3, x=7 and a=2137. Then you plug it into the log part of the equation. log(3)2137=7.
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Vitek1552 [10]

Answer:

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Step-by-step explanations

Using the sin rule

A/sin a = B/sin b

Let A = PQ = 8.5feet

B = QR = x feet

a = R = 90°

b = P = 26°

Substitute the values into the Sin rule

8.5/sin90 = x/sin26

8.5×sin 26 = x × sin 90

8.5×0.4383 = x× 1

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german
Answer: -\frac{169}{120}

I'm assuming you mean this:

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Recall what the cosecant function represents. It is the reciprocal of a sine function, and is often written in this form:

\frac{1}{sinx}

So, using the sine relationship:

cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2sin^{-1}(\frac{-12}{13}))}

Let u = sin^{-1}(\frac{-12}{13})
cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2u)}
= \frac{1}{2sinu \cdot cosu}
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= -\frac{169}{120}
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ira [324]

Answer:

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Step-by-step explanation:

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