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3 years ago

How do i put this in least to greathest 0.5 -1 ,2/3, 1.1

Mathematics

1 answer:

victus00 [196]3 years ago

6 0

-1, 0.5, 2/3, 1.1 is the order of the numbers from least to greatest

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Yan is climbing down a ladder. Each time he descends four rungs on the ladder, he stops to see how much farther he has to go

anastassius [24]

Question:

Yan is climbing down a ladder. Each time he descends 4 rungs on the ladder, he stopped to see how much farther he has to go. If Yan made eight stops with no extra steps, which expression best shows another way to write the product of the number of ladder rungs that Yan and climbed?

4+4+4+4

8+8+8+8

(-1)(4+4+4+4)

(-8) + (-8) + (-8) + (-8)

Answer:

$Total = (-8) +(-8) +(-8) +(-8)$

Step-by-step explanation:

Given

<em></em> $Rungs = -4$ <em> --- It is negative because he is climbing down</em>

$Steps = 8$

Required

An expression for the number of rungs climbed

To do this, we simply multiply the number of rungs by the steps taken.

$Total = Rungs * Steps$

$Total = -4 * 8$

This can be rewritten as:

$Total = -8 * 4$

The product, when written as sum is:

$Total = (-8) +(-8) +(-8) +(-8)$

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3 years ago

5 friends in the classroom want to share a snack. Takis come in bags of 4 pounds. How many pounds of Takis will each friend get

Zarrin [17]

Answer:

The answer is 1.25 pounds equally.

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3 years ago

A music app charged $2 to download the app plus $1.29 per song downloaded. Write and solve a linear equation to find the total c

lara31 [8.8K]

So from what I am seeing is $2 + $1.29 times 30. Which would be $43.7

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3 years ago

you are shopping for disposable cameras to hand out at a party. the daytime cameras costs 2.75 dollars and the flash camera cost

LenKa [72]

The solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)

<h3>Write and solve a compound inequality for this solution. </h3>

The given parameters are:

Daytime cameras = $2.75
Flash camera = $4.25
Number of cameras = 20 cameras
Amount spent = Between $65 and $75

Represent the daytime camera with x and the flash camera with y.

So, we have:

x + y = 20

65 <=2.75x + 4.25y <= 75

Make y the subject in x + y = 20

y = 20 - x

Substitute y = 20 - x in 65 <=2.75x + 4.25y <= 75

65 <=2.75x + 4.25(20 - x) <= 75

Expand

65 <=2.75x + 85 - 4.25x <= 75

This gives

65 <=-1.5x+ 85 <= 75

Subtract 85 from the inequality

-20 <=-1.5x <= -10

Split the inequality

-1.5x >= -20 and -1.5x <= -10

Divide by -1.5

x <= 13.33 and x >= 6.67

Combine the inequality

6.67 <= x <= 13.33

<h3>List all of the solutions that involve whole numbers of cameras.</h3>

In (a), we have:

6.67 <= x <= 13.33

This means that:

x = 7, 8, 9, 10, 11, 12, 13

Recall that:

y = 20 - x

So, we have:

y = 13, 12, 11, 10, 9, 8, 7

So, the solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)