Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.

8 0

3 years ago

Evaluate the expression below at x = 5. x/35 + 5x^2

kramer

Answer:

876/7

Step-by-step explanation:

Just plug the number 5 into the equation and solve. Remember your Order of Operations (PEMDAS).

4 0

2 years ago

Evaluate sin(Tan^-10)

Musya8 [376]

$\tan x=0$ for $x=n\pi$ , where $n$ is any integer. The inverse tangent function returns numbers between $-\dfrac\pi2$ and $\dfrac\pi2$ . The only multiple of $\pi$ in this range is 0, so $\tan^{-1}0=0$ .

Then

$\sin\left(\tan^{-1}0\right)=\sin0=\boxed0$

5 0

3 years ago