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Digiron [165]
3 years ago
8

Find the area please

Mathematics
2 answers:
viva [34]3 years ago
8 0

Answer:

D 30 ft^2

Step-by-step explanation:

This figure is a trapezoid

The area of a trapezoid is given by

A = 1/2 (b1+b2) *h  where b1 and b2 are the lengths of the top and bottom

A = 1/2( 10+5) * 4

   = 1/2 (15)*4

   = 1/2(60)

   = 30 ft^2

TEA [102]3 years ago
6 0

For this case we have that by definition, the area of a trapezoid is given by:A = \frac {(B + b) * h} {2}

Where:

B: It is the major base

b: It is the minor base

h: It's the height

According to the data we have:

B = 10ft\\b = 5ft\\h = 4ft

Substituting:

A = \frac {(10 + 5) * 4} {2}\\A = \frac {15 * 4} {2}\\A = \frac {60} {2}\\A = 30

So, the area of the figure is 30 \ ft ^ 2

ANswer:

Option D

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What is the answer A,B,C,or D it’s worth 13 points
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Write the complex number -2+2i in polar form
FromTheMoon [43]
For polar form you need to find the modulus (length of the vector) and the argument (angle of the vector) and present in form rcis(Arg) or re^Argi

start with the modulus r=sqrt(a^2 +b^2)
                                     =sqrt(-2^2 +2^2)
                                     = sqrt(4+4)
                                     =sqrt(8)
                                     =2sqrt(2)

next the argument, firstly arg=tan(b/a)
                                              = tan(2/2)
                                              =tan(1)
                                             =pi/4 .     (exact values table)
Now consider the quadrant the complex number is in, as it is (-2,2) it is in the second quadrant and as such your Arg value is:
Arg=pi-arg
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     = 3pi/4

add it all together and your complex number in polar form is:
2sqrt2cis(3pi/4)

note: cis is short hand for cos(x)+isin(x), it is possible your tutor would rather you use the complex exponential form which is simply re^Argi and your answer would look like:
2sqrt2e^(3pi/4)i

Also notice the difference between arg and Arg as this often slips students up and always present Arg in prinicple argument form ie -pi<Arg<pi

Hopefully this has been clear enough and good luck

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