This situation shows that <em>the sides lengths of rectangle P is three times longer than the similar sides on Q</em>. <em>x correlates to 4 ft</em>, and <em>9 ft correlates to y</em>.
This means <em>x = 3*4</em> and <em>9 = 3*y</em>.
x = 12 (simplification)
y = 9/3 (division)
y = 3 (simplification)
To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:

<u>Rectangle (a)</u>


<u>Rectangle (b)</u>


<u>Rectangle (c)</u>


<u>Rectangle (d)</u>


Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
Answer:
4
Step-by-step explanation:
4-2
Graph a point at (0,2)
then graph a point at (-2,-1)
With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)