Question

HELP PLEASE

Answer 1

All you need is the definition of conditional probability:

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}$

So

$P(C\mid D)=\dfrac{P(C\cap D)}{P(D)}\iff0.26=\dfrac{P(C\cap D)}{0.22}\implies P(C\cap D)=0.0572$

$P(D\mid C)=\dfrac{P(C\cap D)}{P(C)}\iff0.17=\dfrac{0.0572}{P(C)}\implies P(C)\approx0.34$

and the answer would be B.

Answer 2

Suppose P(C | D) = 0.26, P(D) = 0.22, and P(D | C) = 0.17. What is P(C) Rounded to two decimal places?  

A. 0.42

B. 0.34

C. 0.57

D. 0.68

The answer is B.