Which ordered pair is a solution to the following

What set of transformations could be applied to rectangle ABCD to create A″B″C″D″? 'Rectangle formed by ordered pairs A at negat

CaHeK987 [17]

Answer:

Reflection over the y-axis and rotation of 180°

Step-by-step explanation:

We have,

Rectangle ABCD with co-ordinates A(-4,2), B(-4,1), C(-1,1) and D(-1,2).

It is transformed to a new rectangle A'B'C'D' with co-ordinates A'(-4,-2), B'(-4,-1), C'(-1,-1) and D'(-1,-2).

The graph of both the triangles is shown below.

we see that,

The rectangle ABCD is reflected about y-axis and then rotated 180° to obtain A'B'C'D'.

Reflected about y-axis Rotation of 180°

A= (-4,2) (4,2) A'= (-4,-2)

B= (-4,1) (4,1) B'= (-4,-1)

C= (-1,1) (1,1) C'= (-1,-1)

D= (-1,2) (1,2) D'= (-1,-2)

Hence, the second rectangle is formed by: Reflection over the y-axis and rotation of 180°.

5 0

3 years ago

Read 2 more answers

If two triangles have three corresponding angles and three corresponding sides that are equal in measure, are the two triangles

nikitadnepr [17]

Yes, they are.

If the triangles have three corresponding angles equal means that they are either similar or congruent.

The definition of congruent means that the sides have the same length. That is precisely what the statement says.

So, being the lengths of the corresponding angles the same the two triangles are identical, this is they are congruent.

6 0

3 years ago

Read 2 more answers

Does this graph represent a function? Why or why not?

In-s [12.5K]

B. No, because it fails the vertical line test.

8 0

3 years ago

Replace * with a monomial in such a way, that the trinomial becomes a perfect square. *+12x+1

Mrrafil [7]

Answer: * = 36x^2

Note: Im guessing you're here for rsm struggles. That's how I found this question. I searched the web for the answer to this rsm problem, but I couldnt find it. I was happy to find this brainly link, but annoyed to find it was unanswered. I did the problem, and now i'll help future rsm strugglers out. Thanks for posting this question.

Step-by-step explanation:

Ok, so we know that trinomials like this are squares of binomials. this in mind, we know that it can also be written as (x+y)^2. (also brainly's exponents feature used to be better, if the exponents are confusing you, comment.) Using the (x+y)^2 equation, you know that by simplifying it, you get x^2+2xy+y^2. Basically we're looking for x^2. Using the middle term, 2xy, or 12x in this equation, we can find x. since we know the square root of 1 is 1, we know 12=2x. This is kinda confusing, but basically since the answer is 6, we know that the x-term is 6x. We square 6x and get 36x^2. guaranteed to work on the rsm student portal, i'm in rsm and i just answered this question.

Hope this helps! Also, im not usually too active on brainly unless im looking for HW answers, so if you understand this explanation and you see a confused comment, help out a friend and answer it. Happy holidays!

4 0

2 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago