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chubhunter [2.5K]
3 years ago
5

The dot plots below show the weights of the players of two teams: Based on visual inspection of the dot plots, which team appear

s to have the larger mean weight? Not enough information is available to draw a conclusion. Both groups are similar. Team C Team D

Mathematics
2 answers:
Tresset [83]3 years ago
7 0

Answer:

Team C appears to have the larger mean weight.

Step-by-step explanation:

After seeing the dot plot of two teams i.e. Team C and Team D the conclusion that can be drawn regarding the larger mean of the team is that:

Team C is expected to have larger mean since the dots are for the higher values of weights  and hence will result in higher mean. whereas for team D the dots or frequencies are for smaller weights and hence will result in a less mean as compared to team C.

Hence, Team C appears to have the larger mean weight.

zloy xaker [14]3 years ago
6 0
Team c it has more of its players weighing more than 126
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Forty increased by 4 times a numberis 8 less than 6 times the number. find the number
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4 years ago
Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. H
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Answer:

The answer is b. But you asked for the thought process so...

Step-by-step explanation:

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

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Or, Time = Distance/Speed.

So, the time taken to cover a distance of 50 miles on his first trip = 50/x hr.

And the time taken to cover a distance of 300 miles on his later trip = 300/3x hr.

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Have a great day :)

4 0
3 years ago
Please answer clear i need answers now please
Salsk061 [2.6K]

Answer:

The answers would be:

9: $421.54

10: $872

11: $4,706.66

12: $645.83

13: $626.26

14: $3,981.22

15: $1,110.28

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5 0
3 years ago
The distribution of the weights ofloaves of bread from a certain bakery follow approximately a normaldistribution. Based on a ve
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Answer:

D)

Step-by-step explanation:

ASSUMING NORMAL DISTRIBUTION, LESS THAN 10% AT LOWER END

OF 15.34 MEANS     [DENOTING MEAN BY M AND Standard Deviation. BY S]

M±AS=20%....................M-AS=15.34

FOR 20% LEVEL .......A=1.281........FROM TABLES

M-1.281×S=15.34............................1

SIMILARLY

M±BS=40%...................M+BS=16.31

FOR 40% LEVEL .............B=0.841...................FROM TABLES

M+0.841×S=16.31.............................2

EQN.2 - EQN.1

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S=0.457=0.46

M=15.926= 15.93

HENCE, D IS THE ANSWER

that is D. μ = 15.93, σ =.46

8 0
3 years ago
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