The dot plots below show the weights of the players of two teams: Based on visual inspection of the dot plots, which team appear
s to have the larger mean weight? Not enough information is available to draw a conclusion. Both groups are similar. Team C Team D
2 answers:
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Answer:
<h3>Move all the x terms to one side. Use inverse operations and add 1 5 x 15x 15x to both sides to keep the equation balanced. Solve by working backwards from the order of operations. This means we need to undo the −2 first by adding 2 to both sides of the equation to keep it balanced.</h3>
Answer:
Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:
Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:
Class 66 - 68:
When the computation is completed, the frequency distribution will be:
Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:
<em>See attachment for result of 1-VarStats</em>
