A to the second power is the answer to this problem
Answer:
<h3>Move all the x terms to one side. Use inverse operations and add 1 5 x 15x 15x to both sides to keep the equation balanced. Solve by working backwards from the order of operations. This means we need to undo the −2 first by adding 2 to both sides of the equation to keep it balanced.</h3>
Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Answer:
6647
Step-by-step explanation:
The computation of the advertising revenue for 15 years is shown below:
Given that
r(t) = -18t^2 + 720t - 103
where
t = number of years = 15
now put the value of t in the above equation
= -18(15)^2 + 720(15) - 103
= -4050 + 10,800 - 103
= 6647