A. x intercepts are where the graph hits the x axis or where f(x)=0
0=2x^2-x-10
solve
hmm
we can use the ac method
multiply 2 and -10 to get -20
what 2 numbers muliply to get -20 and add to get -1 (the coefint of the x term)
-5 and 4
split the midd into that
0=2x^2+4x-5x-10
group
0=(2x^2+4x)+(-5x-10)
factor
0=2x(x+2)-5(x+2)
undistribute
0=(x+2)(2x-5)
set each to 0
0=x+2
0=-2
0=2x-5
5=2x
5/2=x
x intercepts are at x=-2 and 5/2 or the points (-2,0) and (5/2,0)
B. ok, so for f(x)=ax^2+bx+c
if a>0, then the parabola opens up and the vertex is a minimum
if a<0 then the parabola opens down and the vertex is a max
f(x)=2x^2-x-10
2>0
opoens up
vertex is minimum
ok, the vertex
the x value of the vertex in f(x)=ax^2+bx+c= is -b/(2a)
the y value of the vertex is f(-b/(2a)) so
given
f(x)=2x^2-x-10
a=2
b=-1
-b/2a=-(-1)/(2*2)=1/4
f(1/4)=2(1/4)^2-(1/4)-10
f(1/4)=2(1/16)-1/4-10
f(1/4)=1/8-1/4-10
f(1/4)=1/8-2/8-80/8
f(1/4)=-81/8
so the vertex is (1/4,-81/8) or (0.25,-10.125)
C. graph the x intercepts and the vertex
the vertex is min and the graph goes through the x intercepts
Answer:
N/4
Step-by-step explanation:
quotient is the same as division
since we don't know what the number is we use n as the variable
so n/4
Hope this helps
Answer:
a. Yes
b. Yes
c. Yes
d. Degree 8
Step-by-step explanation:
a. Yes, n(x) is a polynomial of one single term (also called monomial) because it contains variables raised to positive integers.
b. Yes, m(x) is a polynomial of also one single term (also called monomial) because it contains variables raised to positive integers.
c. The quotient of n(x) / m(x) can be reduced to a polynomial of one single term as follows:
which as can be seen, also contains variables raised to positive integers.
d. The degree of the polynomial resultant is the addition of the powers of all variables present (x and y) which results in: 2 + 6 = 8
Therefore the degree of this polynomial is 8.
C=3.14r^2 that's the formula a
can you make the pic little more clear if you can :)
