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yaroslaw [1]
2 years ago
8

Pls answer these questions .​

Mathematics
1 answer:
Agata [3.3K]2 years ago
3 0

Answer:

1. PQ

2. PR

3. OR/OP

4. OR/OP

5. RO

Step-by-step explanation:

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The equation for the circle below is x^2+y^2=64 what is the length of the circle’s radius
FromTheMoon [43]

Answer:

<h2>r = 8</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

x^2+y^2=64\\\\(x-0)^2+(y-0)^2=8^2

Therefore the center is (0, 0) and the radius r = 8

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2 years ago
Omg please help for brainlist !!!!!!!!!!!!!!!!!!!
zhannawk [14.2K]

Answer:

f(x) is linear

g(x) is exponential

Step-by-step explanation:

A linear function will always have the same rate of change between equally distant points, while an exponential function will have an increasingly large rate of change between equally distant points.

First, look at f(x). All these points are equally distant at 2 units apart on the x-axis, so they can be directly compared:

(-38)-(-18)=-20\\(-58)-(-38)=-20\\(-78)-(-58)=-20

All of these points are the same distance apart on the y, so f(x) must be a linear function.

Now look at g(x). These are also all equally distant at only 1 unit apart.

30-10=20\\90-30=60\\270-90=180

These are very clearly not the same distance apart on the y, so g(x) must be the exponential function.

6 0
2 years ago
Algebra 2 Help! Thank you.
pychu [463]

Answer:

-2

Step-by-step explanation:

f(1)=3(1)-5 = 3-5= -2

4 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
2 years ago
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Whats 14/3 simplified to
devlian [24]

Answer:

4.666667

Step-by-step explanation:

4 0
3 years ago
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