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igor_vitrenko [27]
3 years ago
8

Write (8a^-3)^-2/3 in a simplest form.

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

For this case we have the following expression:

(8a^{-3})^{-\frac{2}{3}}

For power properties we have:

(8^{-\frac{2}{3}} a^{-3*-\frac{2}{3}})

Rewriting the exponents of the expression we have:

(8^{-\frac{2}{3}} a^{3*\frac{2}{3}})

(8^{-\frac{2}{3}} a^2)

(\frac{1}{8^{\frac{2}{3}}} a^2)

Using the cubic root we have:

(\frac{1}{\sqrt[3]{8^2}} a^2)

(\frac{1}{\sqrt[3]{64}} a^2)

(\frac{1}{\sqrt[3]{4^3}} a^2)

Simplifying the expression we have:

(\frac{1}{4} a^2)

Answer:

The equivalent expression is given by:

(\frac{1}{4} a^2)

riadik2000 [5.3K]3 years ago
3 0
<span>So we need to write (8a^-3)^-2/3 in the simplest form. To solve the problem what we must know is that the powers can multiply or: (a^b)^c=a^(b*c). Now we can solve our problem: (8^-2/3)*(a^-3*(-2/3) ) and we can see that 8=2^3 and when we plug that in we get: 2^(3*(-2/3)) * (a^-3*(-2/3) ) and nnow we can write: (2^-2)*(a^-2)=(1/2^2)*(1/a^2)=1/(4*a^2).</span>
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The given equations are
x(t+1)-4t \sqrt{x} =9            (1)
2y+4y^{3/2}=t^{3}+t           (2)

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x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0

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