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3 years ago

13

Hurry!

2 answers:

makvit [3.9K]3 years ago

4 0

Answer:

f(x) = 4|x|

Step-by-step explanation:

The fourth function, f(x) = 4|x| will have a graph narrower than that of |x|.

IRISSAK [1]3 years ago

4 0

Answer: Hello there!

the parent function is f(x) = IxI

now let's analyze the options:

a) f(x) = IxI - 3

this is a displacement of -3 units in the y-axis, so this is not narrower than the parent function

b) f(x) = I x +2I

this is a displacement of -2 units in the x-axis

c)f(x) = 0.5IxI

This means that the value of Y is 0.5 the value of the parent function, this means that when the parent function is 1, this function is equal to 0.5, then this graph will be wider than the one of the parent function.

d)f(x) = 4IxI

now this function increases faster than the parent function when the parent function is equal to 1, this function is equal to 4, so this function is narrower than the parent function.

So the right option is f(x) = 4IxI

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3 years ago

Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and

balu736 [363]

Answer:

(a) The sample size required is 43.

(b) The sample size required is 62.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The margin of error for this interval is:

$MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

(a)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 72 seconds = 1.2 minutes

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the sample size required as follows:

$MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}$

$=[\frac{1.96\times 4}{1.2}]^{2}\\\\=42.684\\\\\approx 43$

Thus, the sample size required is 43.

(b)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 1 minute

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the sample size required as follows:

$MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}$

$=[\frac{1.96\times 4}{1}]^{2}\\\\=61.4656\\\\\approx 62$

Thus, the sample size required is 62.

3 0

3 years ago