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Andre45 [30]
3 years ago
7

On Monday's, Jayda runs between 2 and 5 miles. On Tuesdays, she runs 3 times as far as she runs on the previous Monday. Which in

equality can be used to find X, the distance Jayda could run on Tuesday?
A. 2< 3x < 5
B. 2 < 3x >5
C. 2 < x/3 < 5
D. 2 < r/3 > 5
Mathematics
1 answer:
Flauer [41]3 years ago
3 0

Answer:

A. 2 < 3x < 5

Step-by-step explanation:

<u>On Mondays:</u>

Jayda runs between 2 and 5 miles.

On Tuesdays she runs 3 times as far as she runs on Mondays.

The distance she runs on Tuesdays is given by 2 < 3x < 5

Where x represents the distance she runs on Mondays.

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How do I get this answer?
Keith_Richards [23]

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

  • cos(2x) = cos²(x) -sin²(x)
  • cos²(x) +sin²(x) = 1
  • cos(x) = 1/sec(x)

<h3>Proof</h3>

Starting with the left side, we can transform it into the right side.

  2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}

4 0
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It belongs to the rational numbers.  

It is the ratio of two integers, 2 and 3.

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Ronch [10]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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