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3 years ago

The quotient of 3 times a number and 7 is 15. Find the number pls help me

Mathematics

1 answer:

Ronch [10]3 years ago

4 0

Answer:

it would be 3 times 35 divded by 7 and that answer would give you 15 as the answer so 35 is your missing number

Step-by-step explanation:

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For the data set table 65, 75, 64, 20, 80, 125. what is the mean of this data set table?

Deffense [45]

Answer:

71.5

Step-by-step explanation:

Mean = Sum of data values/How many data values

65+75+64+20+80+125= 429

There are 6 data values in this data set.

429/6 = 71.5

Mean=71.5

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2 years ago

If the legs of a right triangle are given by x2 - y2 and 2xy, then which expression equals the hypotenuse? choose all that apply

11Alexandr11 [23.1K]

Hypothenus = sqrt ((x^2 - y^2)^2 + (2xy)^2) = sqrt(x^4 - 2x^2y^2 + y^4 + 4x^2y^2) = sqrt(x^4 + 2x^2y^2 + y^4) = sqrt(x^2 + y^2)^2 = x^2 + y^2

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2 years ago

A real estate agent works on 7% commission. What is her commission on a house that she sold for $210,600?

loris [4]

To find how much the real estate agent made, we must multiply the two.
Note: It is crucial that you put 7% as a decimal.

$210600*0.07= 14742$

Therefore, the real estate agent made $14,742

Hope this helps!

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3 years ago

Am nev de acest ex urgent va rog

never [62]

Serach it, Thats what I did!

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3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago