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Vikentia [17]
4 years ago
12

How to solve for 6 square root of 5  

Mathematics
2 answers:
NISA [10]4 years ago
5 0
6(radical)5
would be...
(radical)180 which would be about 13.4
Vlada [557]4 years ago
4 0
6 Square root of 5? Are you sure you didn't type that incorrectly?
You might be interested in
Factor 6x4 – 5x2 + 12x2 – 10 by grouping. What is the resulting expression?
lisov135 [29]
Your answer would be the last option, (6x² - 5)(x² + 2).
This is because when you expand it, you get:
6x² × x² = 6x⁴
6x² × 2 = 12x²
-5 × x² = -5x²
-5 × 2 = -10
Which are all the correct terms.

I hope this helps!
7 0
4 years ago
Read 2 more answers
PLS HELP IM DESPARET
vesna_86 [32]

Answer:

19/4 or 4.75

Step-by-step explanation:

Week 1: 1 1/8 = 1.125

Week 2: -2 5/8 = -2.625*

Week 3: 1 3/4 = 1.75

Week 4: -1 1/2 = -1.5

Week 5: 2 1/8 = 2.125*

2 1/8 - (-2 5/8) = 2.125 - (-2.625)

19/4 or 4.75

3 0
3 years ago
2/3 * 10/24*-3 1/8* -4/5
nadya68 [22]

Answer: 25/36

Step-by-step explanation:

Multiply:

2/3 * 10/24 = 20/72 = 5/18

-3 1/8 * -4/5 = 5/2

5/18 * 5/2 = 25/36

7 0
3 years ago
Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
3 years ago
he Pearson family is on vacation in Alaska. Since Mr. Peterson has always wanted to see Mt. McKinley, they are taking a scenic t
Aloiza [94]

Answer:

Mr. Peterson

Step-by-step explanation:

u and one

6 0
3 years ago
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