A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
12 is the answer all u have to do is divide 2
Answer:
predicts that 60% of the students will purchase a hard copy of the book, 25% will print it out from
Step-by-step explanation:
To find the answer you must multiply 45 5 times not by 5 just write down 5 45s and multiply it all together witch is 184528125 :)
