Question

Solve x^2+4x+8. What is the vertex?

Answer 1

Answer:

$(-2,4)$

Step-by-step explanation:

Well to start with there is a vertex formula which is $-\frac{b}{2a} =h$, $f(h)$

Your initial equation is $x^2+4x+8$ where $ax^2+bx+c$. So you would plug in your numbers $-\frac{4}{2(1)}$$=-\frac{4}{2} =-2$ we know know that $h=-2$ so plug in h in $f(-2)$ which would be (-2)^2+4(-2)+8 = 4-8+8 = 4 which would make the vertex $(-2,4)$