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3 years ago

Is y=9x-8 a function

Mathematics

2 answers:

RSB [31]3 years ago

6 0

Yes it is a function

maks197457 [2]3 years ago

3 0

Yes, it is a function

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PLEASE HELP ME PLEASEEEEE

mrs_skeptik [129]

Step-by-step explanation:

radius=diameter/2

r = 6/2 m

 =3m

volume of sphere=4/3πr³

= 4/3π×(3)³

=36π m³

5 0

2 years ago

The graph of the function y = f(x + 26) can be obtained from the graph of

krek1111 [17]

Answer:

left 26 units

Step-by-step explanation:

inside the parentheses means left or right, and it also means opposite direction.

7 0

3 years ago

Read 2 more answers

In ΔVWX, the measure of ∠X=90°, WV = 65, XW = 16, and VX = 63. What ratio represents the tangent of ∠V?

djyliett [7]

Answer:

tanV= adjacent /opposite =

$\frac{16}{63}$

Step-by-step explanation:

4 0

3 years ago

The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha

erastova [34]

Answer:

106.63%.

Step-by-step explanation:

We have been given that at the end of 2005, this price was $513. At the end of 2015, it was $1060.

To find the percentage of the price per ounce of gold increase we will use % increase formula.

$\text{Percent Increase}=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100$

Let us substitute our given values in above formula.

$\text{Percent Increase}=\frac{1060-513}{513}\times 100$

$\text{Percent Increase}=\frac{547}{513}\times 100$

$\text{Percent Increase}=1.0662768031189084\times 100$

$\text{Percent Increase}=106.62768031189084\approx 106.63$

Therefore, the price of per ounce of gold increased by 106.63%.

5 0

2 years ago

Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations.

ki77a [65]

Answer:

The variance is $\sigma ^2 =25$

Step-by-step explanation:

From the question we are told that

The sample size is n = 21

The sum of squares is $SS = 500$

Generally the variance is mathematically represented as

$\sigma ^2 = \frac{SS}{n- 1}$

substituting values

$\sigma ^2 = \frac{ 500}{21- 1}$

$\sigma ^2 =25$

4 0

3 years ago