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Nina [5.8K]
3 years ago
7

Kurt is building a rectangular deck. if the dimensions of the deck are 10 ft by 23 ft, what the length of the diagonal of the de

ck?
Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0
The length of the diagonal of the deck can solved using the pythagorean theorem because the diagonal the sides of a rectangle will form a right triangle. pythagorean theorem states that
C^2 = B^2 + A^2
where C is the hypotenuse or the diagonal of the rectangles
B and A are the sides of the rectangle

C^2 = 10^2 + 23^3
C^2 = 629
C = 25.08 ft

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30 degrees

Step-by-step explanation:

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The sum of 10 and twice Mai’s age
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Can I get the full question please

Step-by-step explanation:

x + y = 10 - - - 1

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4 0
3 years ago
When the beam makes an angle of 40
egoroff_w [7]

A construction crew wants to hoist a heavy 
beam so that it is standing up straight. They 
tie a rope to the beam, secure the base, and 
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<span>Math - Steve Thursday, April 16, 2015 at 6:22pmwe see that the length of the beam is 

8/sin40 = 12.45 ft 

At 60 degrees, the top is 

12.45sin60 = 10.78 ft high 

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3 0
3 years ago
Suppose the first five terms of a sequence are 4, 5, 9, 27, 123. How could the next term in the sequence be generated?
Ipatiy [6.2K]
The <u>correct answer</u> is:

B) by finding the factorial of the term number, then adding 3 to the result.

Explanation:

If we add 3 before finding the factorial, for the first term we would have:

(1+3)! = 4! = 4*3*2*1 = 24.  

This is not the first term, so this is not accurate.

Finding the factorial of the term number and then adding 3, we would have:
1!+3 = 1+3 = 4
2!+3 = 2*1+3 = 2+3 = 5
3!+3 = 3*2*1+3 = 6+3 = 9
4!+3 = 4*3*2*1+3 = 24+3 = 27
5!+3 = 5*4*3*2*1+3 = 120+3 = 123

This is the correct answer.
4 0
3 years ago
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