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3 years ago

Which transformation shows that the two given circles are similar?

Mathematics

1 answer:

gregori [183]3 years ago

3 0

Circle A -- center(2, 0), radius 8 Circle A' -- center(-1, 5), radius 3

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Please help this is super urgent!!!

Leviafan [203]

Answer:

A number line with an open circle on 2, a closed circle on 6, and shading in between

Step-by-step explanation:

Given:

3x+1 > 7 → inequality A

4x ≤ 24 → inequality B

Step 1

Solve inequality A

3x+1>7

3x>7-1

x>2

the solution is the interval------> (2,∞)

Step 2

Solve inequality B

4 x ≤ 24

4 ≤ 6

the solution is the interval------> (-∞,6]

Step 3

Find the solution of the compound inequality

Solution A ∩ Solution B

(2,∞) ∩ (-∞,6]=(2,6]

therefore

The answer is A number line with an open circle on 2, a closed circle on 6, and shading in between

3 0

2 years ago

Read 2 more answers

A rectangle initially has width 7 meters and length 10 meters and is expanding so that the area increases at a rate of 8 square

Tems11 [23]

Answer:

The length of rectangular is increasing at a rate 0.5714 meters per hour.

Step-by-step explanation:

We are given the following in the question:

Initial dimensions of rectangular box:

Length,l = 10 m

Width,w = 7 m

$\dfrac{dA}{dt} = 8\text{ square meters per hour}\\\\\dfrac{dw}{dt} = 40\text{ centimeters per hour} =0.4\text{ meters per hour}$

We have to find the rate of increase of length.

Area of rectangle =

$A = l\times w$

Differentiating we get,

$\displaystyle\frac{dA}{dt} = \frac{dl}{dt}w + \frac{dw}{dt}l$

Putting values, we get,

$8 = \dfrac{dl}{dt}(7) + (0.4)(10)\\\\\dfrac{dl}{dt}(7) = 8 -4\\\\\dfrac{dl}{dt} \approx 0.5714$

Thus, the length of rectangular is increasing at a rate 0.5714 meters per hour.

5 0

3 years ago

Convert 0.4 to a percent. % Check Explain

Orlov [11]

Answer:

40%

Step-by-step explanation:

0.4=0.40

0.40×100

=40%

5 0

2 years ago

Read 2 more answers

Ilia_Sergeevich [38]

Answer:

D. y = |x| – 5.5

Step-by-step explanation:

6 0

3 years ago

What is the 9th term of the following geometric sequence? 7/9,-7/3,7,-21,63 ??????

dmitriy555 [2]

Given:

The geometric sequence is:

$\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...$

To find:

The 9th term of the given geometric sequence.

Solution:

We have,

$\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...$

Here, the first term is:

$a=\dfrac{7}{9}$

The common ratio is:

$r=\dfrac{a_2}{a_1}$

$r=\dfrac{\dfrac{-7}{3}}{\dfrac{7}{9}}$

$r=\dfrac{-7}{3}\times \dfrac{9}{7}$

$r=-3$

The nth term of a geometric sequence is:

$a_n=ar^{n-1}$

Where, a is the first term and r is the common ratio.

Substitute $a=\dfrac{7}{9},r=-3,n=9$ to find the 9th term.

$a_9=\dfrac{7}{9}(-3)^{9-1}$

$a_9=\dfrac{7}{9}(-3)^{8}$

$a_9=\dfrac{7}{9}(6561)$

$a_9=5103$

Therefore, the 9th term of the given geometric sequence is 5103.

5 0

3 years ago