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3 years ago

This is so confusing

Mathematics

2 answers:

Nesterboy [21]3 years ago

8 0

Step-by-step explanation:

d-7=4d+3

e

e(d-7)=4d+3

de-7e=4d+3

ed-4d=3+7e

d(e-4)=3+7e

d=3+7e

(e-4)

hope it helps.

shutvik [7]3 years ago

4 0

Answer:

first one should be:

ed-4d

then the one in the brackets should be:

e-4

the final answer should be

e-4

the full question is the picture

Step-by-step explanation:

ed-7e=4d+3

ed-4d=3+7e

d(e-4)=3+7e

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Answer:

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Step-by-step explanation:

gift + lunch + (skittles * count) ≤ $21

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12.75 + 0.40x ≤ 21

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4 0

3 years ago

Read 2 more answers

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photoshop1234 [79]

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Step-by-step explanation:

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3 years ago

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AleksAgata [21]

Answer:

Step-by-step explanation:

First set up your data in order

0,0,0,0,1,1,1,2,2,2,2,3,3

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Hope this helps!

6 0

2 years ago

There are 10 marbles in a paper bag, 6 of which are red. The rest are blue. You play a game with your friend. If you draw a red

maria [59]

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3 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago