Answer: Triangle ABC and Triangle ECD
Step-by-step explanation:
In Triangle ABC and Triangle ECD
BD=CD and AD=ED [given in the figure]
∠BDA=∠EDC [Vertically opposite angles are equal]
⇒ΔABC ≅ ΔECD [By SAS postulate]
SAS postulate or Side Angle Side postulate tells that if two sides and their included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
Answer:
a, c, b
Step-by-step explanation:
ITS CORRECT TRUST MEEE
Answer:
23052
Step-by-step explanation:
3. The original sequence
TAC - CGC - TTA - CGT - CTG - ATC - GCT
codes for
tyr - arg - leu - arg - leu - ile - ala
while the mutated sequence codes for
TAC - CGC - TTA - TTA - TTA - CGT - G<u>CT</u> - <u>G</u>CT - ATC - GCT
tyr - arg - leu - leu - leu - arg - <u>ala</u> - ala - ile - ala
There are several frameshift mutations involved here:
• the first inserts 6 bases (TTA - TTA)
• the second inserts 1 base (G) before the CTG triplet (underlined)
• the third inserts 2 bases (CT) after the CTG triplet
4. The original sequence is the same as before. The mutated sequence
TAC - CGC - TAA - TTA - TTA - CGT - G<u>CT</u> - <u>G</u>CT - ATC - GCT
codes for
tyr - arg - STOP - leu - leu - arg - ala - ala - ile - ala
Then
• there is a (nonsense) point mutation that swaps T for A in the original TTA triplet (nonsense since it produces a stop codon that would halt replication/expression)
• there is a frameshift mutation that inserts 3 bases (TTA)
as well as two other frameshift mutations that also occurred in the previous part.
