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ddd [48]
3 years ago
13

Need help with full explanation first to answer extra points!!!

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0

Answers:

<h2>1. 35 </h2><h2>2. 12</h2>

Step-by-step explanation:

Those brackets indicate absolute value. Absolute value is the distance of a number from 0 on the number line. In other words, negatives don't matter. There is also no such thing as a negative absolute value.

-2     -1      0      1       2

Both -2 and 2 are the same distance from 0, just in the opposite direction. Both numbers have the same absolute value, which is 2.

Hope This helps. If it did, then....

<em>PLEASE MARK BRAINLIEST</em>

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Answer:

6(25 - 3M)

Thats the correct answer

5 0
3 years ago
I need help really bad help me pls
olasank [31]

Answer: w= 13

Step-by-step explanation: 8+5 is 13

3 0
2 years ago
Read 2 more answers
state domain and range, intercepts, relative max and relative mins points and values, intervals of increase and decrease, interv
Anarel [89]

The domain of the graph is -∝ < x < ∝ and the range of the graph is -∝ < y < ∝. Also, the graph has no axis of symmetry

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

From the graph, we can see that the y values extend indefinitely

So, the range of the graph is -∝ < y < ∝

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

  • x-intercept = -4, -2 and 2
  • y-intercept = -9

<h3>Relative max and relative mins points and values, </h3>

The graph has a relative maximum at (3, 3) and the relative minimum are (0.5, 10)

<h3>Intervals of increase and decrease, </h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

  • Increasing interval: (0.5, ∝) and (-∝, -3)
  • Decreasing interval: (-3, 0.5)

<h3>Intervals of positive and negative,</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

  • Positive interval: (-4, -2) and (2, ∝)
  • Negative interval: (-∝, -4) and (-2, 2)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the graph has no axis of symmetry

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

  • As x ⇒ ∝, f(x) ⇒ +∝
  • As x ⇒ -∝, f(x) ⇒ -∝

Read more about functions at:

brainly.com/question/3951754

#SPJ1

3 0
1 year ago
What is the relationship between the discriminant of a quadratic and its graph?
faltersainse [42]

Answer:

In a quadratic equation of the shape:

y = a*x^2 + b*x + c

we hate that the discriminant is equal to:

D =  b^2 - 4*a*c

This thing appears in the Bhaskara's formula for the roots of the quadratic equation:

x = \frac{-b +-\sqrt{b^2 - 4ac} }{2a}

You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)

If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)

If D > 0 we have two different roots, so the graph touches the x-axis in two different points.

4 0
3 years ago
X^2+1/2x+____=2 + ____
natali 33 [55]

Answer:  x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}

Step-by-step explanation:

Given the following Quadratic equation:

x^2+\frac{1}{2}x=2 +

You can change its formed by Completing the square.

In order to do Complete the square, you can follow these steps:

1. You can identify that:

b=\frac{1}{2}

2. Then, you can find (\frac{b}{2})^2. This is:

(\frac{\frac{1}{2}}{2})^2=(\frac{1}{4})^2=\frac{1}{16}

3. Now you must add \frac{1}{16} to both sides of the Quadratic equation in order to keep the balance. Then:

x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}

4. Finally, simplifying by actoring and adding the like terms, you get:

(x+\frac{1}{4})^2=\frac{9}{4}

3 0
3 years ago
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