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3 years ago

Order these numbers from least to greatest.

2 answers:

7 0

7 9/11 = 7.81 with a line over the 81 because it is repeating
15/720 = 0.020
7.58
7.812

least to greatest : 15/720, 7.58 , 7.812 , 7 9/11

stealth61 [152]3 years ago

4 0

7,9/11,15/729,7.58,7.812. I hope dis is right XD

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Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable

wel

This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = $\frac{999,999}{6} = 166666$
N(c₂) = $\frac{999,999}{4} = 250000$
∴N(c₁c₂) = $\frac{999,999}{24} = 41667$
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4

8 0

4 years ago

evaluate if s equals 5 and 2 equals 7 3s^2 +t^2 -3 please show how you got your work I will get brainiest

iragen [17]

$3 {(5)}^{2} + ( {7)}^{2} - 3 \\ 3(25) + 49 - 3 \\ 75 + 49 - 3 \\ = 121$

6 0

3 years ago

Prove the following identity true. Show work.

yulyashka [42]

Answer:

The Pythagorean identity states that

$\sin^2 t + \cos^2 t = 1$

Using that we can rewrite the left denominator as:

$1 - \sin^2 t$

Which can be factored as

$(1 - \sin t)(1+ \sin t)$

The numerator we can expand as:

$(1 - \sin t)(1 - \sin t)$

On the right hand side, let's multply numerator and denominator with (1 - sin t):

The total formula then becomes:

$\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}$

There you go... left and right are equal.

3 0

3 years ago

Read 2 more answers

How can you tell when a pattern shows counting on by tens?

s2008m [1.1K]

Counting by Tens with numbers 10, 20, 30, 40, 50, 60, 70, 80, 90 Counting by Tens with words ten, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, one hundred Number Patterns when counting by Tens When you count by tens the numbers create a pattern. All the numbers end with a zero. The first digits are just like the numbers when you count (1, 2, 3, 4, 5, etc.). This pattern gives the numbers 10, 20, 30, 40, 50, etc. found from: http://www.aaamath.com/k4c_cox1.htm

8 0

3 years ago

Read 2 more answers

I’m thinking of a number. When you multiply it by 3 and subtract 10 you will get a number less than 5. Form an inequality and so

sweet-ann [11.9K]

Answer:

$3x-10$

Step-by-step explanation:

Let x be equal to the number.

We can use what the question gives us to directly form a mathematical statement. When you multiply it by 3 (3x) and then subtract 10 (3x-10) you will get a number less than 5 (<5). Using this, our mathematical statement would look like this:

$3x-10$

To find the range of possible values, we must solve the inequality and isolate x.

$3x-10$

Add 10 to both sides

$3x-10+10$

Divide both sides by 3

$\frac{3x}{3}$

I hope this helps!

4 0

3 years ago