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Vesnalui [34]
3 years ago
6

Order these numbers from least to greatest.

Mathematics
2 answers:
lara [203]3 years ago
7 0
7 9/11 = 7.81 with a line over the 81 because it is repeating
15/720 = 0.020
7.58
7.812

least to greatest : 15/720, 7.58 , 7.812 , 7 9/11
stealth61 [152]3 years ago
4 0
7,9/11,15/729,7.58,7.812. I hope dis is right XD
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a person pays a loan of Rs. 3900 in monthly installments each in installment being less than the former by Rs. 20 ,the amount of
musickatia [10]

Answer:

15 installments

Step-by-step explanation:

3900 = Σ \left \ {{x=n} \atop {x=1}} \right.   400 - 20*(n - 1)

4 0
2 years ago
Does anyone know the formula for finding the area of a circles sector
NemiM [27]
Area=(Theta/2) * r^2 This should be it, obviously Theta is your angle and you should use radiants in theory.
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3 years ago
A rectangle has a length five more than twice the width. If the perimeter is 22 units find the width and length
PtichkaEL [24]

Set the following: Length = L    Width = W

The length is twice the width:    L = 2*W     or:  W = L/2

Perimeter: P = 60ft = 2*L + 2*W

Substituting L for W in the perimeter equation gives:

P = 60ft = 2*L + 2*(L/2) = 2*L + L = 3L

L = 60ft/3 = 20ft    W=L/2=20ft/2=10ft

Verify result:  Perimeter= P = 60ft = 2L + 2W = 2*20ft +2*10ft = 40ft+20ft = 60ft

The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft)^2

-Rosie

3 0
3 years ago
Leroi and Sylvia both put $100 in a savings account. Leroi decides he will put in an additional $10 each week. Sylvia decides to
Nimfa-mama [501]
Sylvia puts in $121.

10% of (multiply) $210.
210= 100 each person plus an additional ten from Leroi
so .10*210 = $21. 
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6 0
3 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

g(y) = \frac{y-5}{y^2-3y+15}

According to the quotient rule:

d(\frac{f(y)}{h(y)})  = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}

Applying the quotient rule:

g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}

The values for which g'(y) are zero are the critical points:

g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10

The critical values are y = 0 and y = 10.

5 0
3 years ago
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