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3 years ago

P(x) --->p(x+6)+3 ? what would the graph look like?

1 answer:

5 0

<span>given that P(x) --->p(x+6)+3
</span>
∴ x will become x+6
and P(x+6) will become P(x+6)+3
<span />
So, The graph of [p(x+6)+3] will be the same as the graph of [p(x)] but shifted 6 units to the left then shifted 3 units up
OR by another words, we need to make axis translations from (0,0) to (-6,3)

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Write the equation of the line that is PARALLEL to y = -4x + 5 and passes through the point (-2,-1)

Salsk061 [2.6K]

Answer: y = -4x-9

Step-by-step explanation:

parallel slope means it's the same slope as the given equation

y+1=-4(x+2)

y+1 = -4x-8

y = -4x-9

6 0

2 years ago

Find the solution set of this inequality. Enter your answer in interval notation using grouping symbols. -2x+5<3

Andrej [43]

Answer:

( 1 , ∞ )

Step-by-step explanation:

Interval notation rounds up to infinite

8 0

2 years ago

Read 2 more answers

Will rate7 you brainliest

Vilka [71]

Answer:

$\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }$

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

$\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)$

$\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)$

$\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)$

$\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)$

Now, let's compute the product.

$\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}$

So the correct answer is the first one.

Thank you.

7 0

3 years ago

Megan cut a string into 4 equal pieces. Each piece is 4 fifths of a foot long. How many feet long was the string before Megan cu

worty [1.4K]

Answer:

$Total = 3\frac{1}{5}ft$

Step-by-step explanation:

Given

$Pieces = 4$

$Size = \frac{4}{5}ft$

Required

Determine the total size of the string

To do this, we multiply the number of pieces by the length of each piece.

$Total = Pieces * Size$

$Total = 4 * \frac{4}{5}ft$

$Total = \frac{4 * 4}{5}ft$

$Total = \frac{16}{5}ft$

Convert to mixed number

$Total = 3\frac{1}{5}ft$

5 0

2 years ago

Find the orthocenter of △ABC. A(2, 3), B(−4, −3), C(2, −3)

weqwewe [10]

ANSWER

$\boxed { A. \: \: (2,-3) }$

EXPLANATION.

The orthocenter is the point of intersection of any two altitudes of the triangle.

First, you need to determine the slope of each side of the triangle.

△ABC has vertices A(2, 3), B(−4, −3), C(2, −3).

$slope \: of \: AB = \frac{3 - - 3}{2 - - 4} = \frac{6}{6} = 1$

$slope \: of \: AC = \frac{ 3 - - 3}{2 - 2} = \frac{6}{0}$

This line has undefined slope, which means it is a vertical line.

$slope \: of \: BC = \frac{ - 3 - - 3}{ 2 - - 4} = \frac{0}{6} = 0$

The slope of this line is zero, meaning the line is a horizontal line.

This implies that side BC and side AC of the given triangle are perpendicular and will intersect at C since they are the altitudes of triangle ABC.

Hence the orthocentre is

$(2,-3)$

See diagram in attachment.

5 0

2 years ago