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allsm [11]
3 years ago
14

A sector of a circle has a central angle of 60◦ . find the area of the sector if the radius of the circle is 3 mi.

Mathematics
1 answer:
kumpel [21]3 years ago
4 0
The area of sector is 4.71mi^2
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THIS IS MY LAST QUESTION. Okay, im a bit anxious to get this done. Ive done half the problem, I just need the other half.
igor_vitrenko [27]

Answer:

umef leaf ninja the frog held a

7 0
3 years ago
A movie theater earned $3,600 in sold-out ticket sales for the premiere of a new movie. VIP tickets cost $20 per person and regu
julia-pushkina [17]

There are 300 seats in the theater.

Step-by-step explanation:

Given,

Cost of one VIP ticket = $20

Cost of one regular ticket = $8

Worth of sold out tickets = $3600

Let,

x represent the number of VIP tickets sold

y represent the number of regular tickets sold

20x+8y=3600     Eqn 1

y = 2x                   Eqn 2

Putting value of y from Eqn 2 in Eqn 1

20x+8(2x)=3600\\20x+16x=3600\\36x=3600

Dividing both sides by 36

\frac{36x}{36}=\frac{3600}{36}\\x=100

Putting x=100 in Eqn 2

y=2(100)\\y=200

Total = x+y = 100+200 = 300

There are 300 seats in the theater.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/10633485
  • brainly.com/question/10672611

#LearnwithBrainly

6 0
3 years ago
Help me with these questions
Elena L [17]

Answer: a = 4, b = 163,422

<u>Step-by-step explanation:</u>

P = P_{0} e^{kt}   P is the new population, P₀ is the initial population, k is the growth rate, t is the time elapsed.

Part a) What do we know?

P = 7003

P₀ = unknown

k = .21 <em>(converted 21% into a decimal)</em>

t = 36 yrs <em>(2006 - 1970) </em>

P = P_{0} e^{kt}   <em>need to solve for P₀</em>

7003 = P_{0} e^{(.21)(36)}

7003 = P_{0} e^{7.56}

7003 = P₀ (1920)

\frac{7003}{1920} = P_{0}

3.6 = P₀

rounded to the nearest whole number = 4

Part b) What do we know?

P = unknown

P₀ = 7003

k = .21 <em>(converted 21% into a decimal)</em>

t = 15 yrs <em>(2021 - 2006) </em>

P = P_{0} e^{kt}   <em>need to solve for P₀</em>

P = 7003 e^{(.21)(15)}

P = 7003 e^{3.15}

P = 7003(23.33)

P = 163,422.46

rounded to the nearest whole number = 163,422

*************************************************************

Answer: 2, -1

<u>Step-by-step explanation:</u>

eˣ² = eˣ * e²

eˣ² = eˣ⁺²

x² = x + 2

x² - x - 2 = 0

(x - 2)(x + 1) = 0

x - 2 = 0      or      x + 1 = 0

 x = 2          or         x = -1

Check both answer for validity:

eˣ² = eˣ⁺²

e⁴ = e⁴     or   e¹ = e¹

TRUE             TRUE

*****************************************

Answer: 0 = ln 1

<u>Step-by-step explanation:</u>

e^{-10} = \frac{1}{e^{10}}

ln(e^{-10}) = ln(\frac{1}{e^{10}})

-10 = ln 1 - 10   <em>log rules say division is subtraction</em>

 0 = ln 1



5 0
3 years ago
Factor the expression.<br> x squared-25
grin007 [14]
X2<span> - 25 = x</span>2<span> - 5</span>2<span> = (x - 5)(x + 5)

</span>
4 0
4 years ago
A 5-pound sack of potatoes is supposed to weigh 5
TEA [102]

Answer:

t test for one mean.

met

met

met

Step-by-step explanation:

5 0
2 years ago
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