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NikAS [45]
3 years ago
13

relationship between two quantities in which the ratio of one quantity to the other quantity quantity is constant

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0
<span>Proportional Relationship should be the correct answer.</span>
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Find the fraction of stundents enrolled in each language
blondinia [14]

Fraction of students enrolled in Chinese = \frac{51}{126}

Fraction of students enrolled in French = \frac{33}{126}

Fraction of students enrolled in Spanish = \frac{42}{126}

Solution:

Total number of students = 51 + 33 + 42

                                          = 126

Number of students enrolled in Chinese = 51

Fraction of students enrolled in Chinese

             $=\frac{\text{Number of students enrolled in Chinese}}{\text{Total number of students}}

             $=\frac{51}{126}

Fraction of students enrolled in Chinese = \frac{51}{126}

Number of students enrolled in French = 33

Fraction of students enrolled in French

             $=\frac{\text{Number of students enrolled in French}}{\text{Total number of students}}

             $=\frac{33}{126}

Fraction of students enrolled in French = \frac{33}{126}

Number of students enrolled in Spanish = 42

Fraction of students enrolled in Spanish

             $=\frac{\text{Number of students enrolled in Spanish}}{\text{Total number of students}}

             $=\frac{42}{126}

Fraction of students enrolled in Spanish = \frac{42}{126}

7 0
3 years ago
46/16 as a mixed number
daser333 [38]
2 14/16. .........................That's the answer
5 0
3 years ago
Read 2 more answers
5% of what number is 300?
svlad2 [7]

Answer:

6000

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Hello I don’t understand question 9 a and b. Please show working out.<br> Thanks
brilliants [131]
A) I would make the positive integer x and then form an equation.

x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6

Since the question asks for a positive integer the answer is 7.

B) two positive numbers x and y.

X - y = 3
x^2 + y^2 = 117

Use these simultaneous equations to figure out each number.

Rearrange the first equation

x = y + 3

Then substitute it into the second equation.

(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)

This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.

Use y to find x

x = y + 3
x = 6 + 3
x = 9

So the answers are x = 9 and y = 6.
3 0
3 years ago
Please solve for w, p=21+2w
sp2606 [1]

Answer:

w = (p - 21)/2

Step-by-step explanation:

Rearrange the equation so that it is equal to w.

p = 21 + 2w

p - 21 = (21 + 2w) - 21

p - 21 = 2w

(p - 21)/2 = (2w)/2

(p - 21)/2 = w

w = (p - 21)/2

3 0
3 years ago
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