
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
Answer:
Step-by-step explanation:
w + g = 52
w = 4g - 3
(4g - 3) + g = 52
5g - 3 = 52
5g = 52 + 3
5g = 55
g = 55/5
g = 11....there are 11 green marbles
w + g = 52
w + 11 = 52
w = 52 - 11
w = 41 <=== there are 41 white marbles
6 pencils = 2 rulers
1ruler= 2 eraser
12 pencil = 4 rulers
4rulers=8 eraser
so 8 erasers are equal to 12 pencils