<h2>
Answer:</h2>
The values of sinθ and tanθ are:
and
<h2>
Step-by-step explanation:</h2>
It is given that:
where
i.e. the angle θ lie in the second quadrant.
Also, we know that in the second quadrant sine and cosecant function is positive.
whereas cosine,secant, tangent and cotangent functions are negative.
Now, we know that:
i.e. here
Hence, we have:
Also,
Now, on rationalizing we have:
X = 7.............................
The perimeter of the polygon will be given by:
Perimeter=distance around the figure
Thus the perimeter will be:
P=9.9+(9.9-5.9)+5.9+15.9+(15.9-4.6)+4.6
P=9.9+4+5.9+15.9+11.3+4.6
P=51.6
Answer: 51.6 units
Answer:
B. x = 53 degrees.
Step-by-step explanation:
The external angles of all polygons add up to 360 degrees, so:
x + 120 + 90+ 97 = 360
x = 360 - 90 - 120 - 97
x = 53 degrees.
For the first one, you did good. I will just suggest a couple things.
Statement Reason
JK ≅ LM Given
<JKM ≅ < LMK Given (You did both of these steps so well done.)
MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)
ΔJMK ≅ ΔLKM SAS
Problem 2: (You also have a lot of great stuff here.)
Statement Reason
DE ║ FG Given
DE ≅ FG Given
<DEF≅<FGH Given
<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)
ΔEDF≅ΔGFH ASA
<DFE≅<FHG CPCTC
