True. this is a danger in the internet.stay safe
Once a source code is compiled to machine code, it becomes specific to the platform targeted, to the machine architecture. So, this is the reason why the <span>system software is dependent on the underlying machine architecture. It is t</span><span>he reason why you cannot run a Linux program on Windows , for example. </span>Source code can be compiled to target different architectures and executable formats. <span>
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Answer:
Hi, I'm going to put the code answer here and you put in the corresponding line to not copy all the code in the answer.
replace the following line or adjust to the following code
/*
* CODE HERE
while(personSelect <= 0 || personSelect > 5) {
System.out.println("Wrong number, try to input the number in range 1 to 5" );
personSelect = scan.nextInt();
}
if(personSelect == 1){
person1.setGpa(newGPA);
printInfo()
}
else if(personSelect == 2){
person2.setGpa(newGPA);
printInfo()
}
else if(personSelect == 3){
person3.setGpa(newGPA);
printInfo()
}
else if(personSelect == 4){
person4.setGpa(newGPA);
printInfo()
}
else {
person5.setGpa(newGPA);
printInfo()
}
*/
Explanation:
According to the description of code, we have to add some lines to resolve the questions.
a):
In base on the input, we have to modify the <em>attribute GPA</em> with the method <em>setGpa</em> depending on the person chosing. We call the person chosen before and also call the method setGpa( ) and pass as <em>parameter</em> the GPA value obtained in tha last input
b)
In this case we have to <em>create a loop</em> for iterate the times that is necesary to get a value of person that is permit in <em>range 1 to 5</em>, and hence that we create and individual if condition to assign the GPA to the person chosen.
I hope it's help you.
Answer:
multi_exit_discriminator
Explanation:
When two routers are connected to the same internet exchange or generally, two routers are used in the same location for connection to external networks, it's best practice to set up BGP sessions to or from each router.
Answer:
d)myints [1] = something.
Explanation:
The elements in the array are stored serially.Every element in the array is indexed and the indexing start form 0 to size-1.So to access the second element in the array it's index will be 1.So to access the second element we have to write arrayname[1];
In our case the name of the array is myints.
Hence the answer is myints[1]=something