The first picture is for number 1 and the second one for number 2.
Answer:
A
Step-by-step explanation:
how long is the ball in the air ?
that is the same as asking : after how many seconds will the ball hit the ground (= reach the height of 0) ?
so, that means we need to find the zero solution of h(t).
at what t is h(t) = 0 ?
when at least one of the factors is 0 :
2(-2 - 4t)(2t - 5)
we have 3 factors
2 : can never be 0.
(-2 -4t) : can only be 0 for negative t, which does not make sense in our scenario (we cannot go back in time, only forward).
(2t - 5) : is 0 when 2t = 5 or t = 2.5
so, A is the right answer.
FYI : the starting height (on the hill) is given by t = 0 :
2(-2 - 0)(0 - 5) = 2×-2×-5 = 20 ft
Answer:
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
C: The graph shows that there is no movement for the first few minutes, and then the distance from home decreases (rather than increases).
Answer:
x = -6
Step-by-step explanation:
The solution means to solve for x. To solve for "x", isolate the variable. This means to separate it from everything else. Do this using reverse operations in reverse BEDMAS order.
2/3 x + 5 = 1
2/3 x + 5 - 5 = 1 - 5 Subtract 5 from both sides
2/3 x = -4
(2/3 x) / (2/3) = (-4) / (2/3) Divide both sides by 2/3
x = (-4) / (2/3)
x = -6 Solution
